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java - Spring 和 Hibernate 的 LazyInitialization 异常

转载 作者:行者123 更新时间:2023-12-01 16:08:35 25 4
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我认为我缺少一些有关 Hibernate 工作原理的基本知识,特别是延迟加载。我的问题是调试,因为我不确定这是 Hibernate 问题还是变相的 Spring 问题。我想在进行一些重大重构之前我应该​​在这里问一下。

我有两个实体。一个以 OneToMany 关系保存另一个的集合。对于我的网页,我希望获取所有第一个实体,然后获取每个实体的关联实体集并显示它们。

我相信我的问题是这样的:我使用 JpaTemplate 来查找所有实体。这工作正常,但是由于延迟加载,我没有获得关联的相关实体集。在我看来(jsp)我想访问这个集合,但当然它是空的,因为它是延迟加载的。现在,我收到一个 LazyInitialization 异常,表明事务已结束。对我来说这是有道理的,当然交易现在应该结束了。问题是,如果事务结束,关联集如何延迟加载?

实体类:

@Entity
public class LearningEntry implements Serializable {

private Long id;
String imagePath = "";
Set<Sample> samples = null;

//------------------------------
// Constructors
//------------------------------
public LearningEntry(){
imagePath = "";
samples = new HashSet<Sample>();
}

//------------------------------
// Instance Methods
//------------------------------
public void addSample(Sample s){
samples.add(s);
}

public void removeSample(Sample s){
samples.remove(s);
}

//------------------------------
// Setters and Getters
//------------------------------

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
public Long getId() {
return id;
}

public void setId(Long id) {
this.id = id;
}

//@Column(name = "wisi_LE_IMAGEPATH", length = 100, nullable = false)
public String getImagePath() {
return imagePath;
}

public void setImagePath(String imagePath) {
this.imagePath = imagePath;
}

// TODO - ONly works with fetch type EAGER
//@OneToMany(fetch = FetchType.EAGER, cascade = {CascadeType.PERSIST, CascadeType.MERGE})
@OneToMany(cascade = {CascadeType.PERSIST, CascadeType.MERGE})
public Set<Sample> getSamples() {
return samples;
}

public void setSamples(Set<Sample> samples) {
this.samples = samples;
}
}

示例实体

@Entity
public class Sample implements Serializable {


private Long id;
Date creationDate;
String audioFileLocation;
Integer votes;
String description;

public Sample(){
creationDate = new Date();
audioFileLocation = "";
votes = 0;
description = "";
}

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
public Long getId() {
return id;
}

public void setId(Long id) {
this.id = id;
}

public String getAudioFileLocation() {
return audioFileLocation;
}

public void setAudioFileLocation(String audioFileLocation) {
this.audioFileLocation = audioFileLocation;
}

@Temporal(TemporalType.DATE)
public Date getCreationDate() {
return creationDate;
}

public void setCreationDate(Date creationDate) {
this.creationDate = creationDate;
}

public String getDescription() {
return description;
}

public void setDescription(String description) {
this.description = description;
}

public Integer getVotes() {
return votes;
}

public void setVotes(Integer votes) {
this.votes = votes;
}
}

DAO 类:学习EntryDAO

@Transactional
public class JpaLearningEntryDAO implements LearningEntryDAO{

private JpaTemplate jpaTemplate;

public JpaLearningEntryDAO(){
}

public void setJpaTemplate(JpaTemplate jpaTemplate){
this.jpaTemplate = jpaTemplate;
}

@Override
//@Transactional
public void delete(Long leId) {
LearningEntry dp = jpaTemplate.find(LearningEntry.class, leId);
jpaTemplate.remove(dp);
}

@Override
@SuppressWarnings("unchecked")
//@Transactional
public List<LearningEntry> findAll() {
return jpaTemplate.find("from LearningEntry");
}

@Override
//@Transactional
public LearningEntry findById(Long leId) {
return jpaTemplate.find(LearningEntry.class, leId);
}

@Override
//@Transactional
public LearningEntry store(LearningEntry dp) {
return jpaTemplate.merge(dp);
}

@Override
@SuppressWarnings("unchecked")
//@Transactional
public void deleteAll(){
throw new RuntimeException("deleteAll not implemented");
}
}

示例 DAO

@Transactional
public class JpaSampleDAO implements SampleDAO{

private JpaTemplate jpaTemplate;

public JpaSampleDAO(){}

public void setJpaTemplate(JpaTemplate jpaTemplate){
this.jpaTemplate = jpaTemplate;
}

@Override
//@Transactional
public void delete(Long sampleId) {
Sample dp = jpaTemplate.find(Sample.class, sampleId);
jpaTemplate.remove(dp);
}

@Override
@SuppressWarnings("unchecked")
public List<Sample> findAll() {
return jpaTemplate.find("from Sample");
}

@Override
public Sample findById(Long sampleId) {
return jpaTemplate.find(Sample.class, sampleId);
}

@Override
public Sample store(Sample dp) {
return jpaTemplate.merge(dp);
}

@Override
@SuppressWarnings("unchecked")
public void deleteAll(){
throw new RuntimeException("deleteAll not implemented");
}
}

Controller

@RequestMapping(value = "/index.htm", method = RequestMethod.GET)
public ModelAndView sayHello(HttpServletRequest request,
HttpServletResponse response) throws ServletException, IOException {

Map<String, Object> model = new HashMap<String, Object>();
List<LearningEntry> le = learningEntryService.getLearningEntries();
model.put("learningEntries", le);
return new ModelAndView("main", model);
}

查看

<section id="content" class="body">
<ol id="posts-list" class="hfeed">
<c:forEach items="${learningEntries}" var="learningEntry">
<li>
<table class="wisiEntry">
<tr>
<td class="pictureCell">
<img class="wisiEntry-pic" src="${learningEntry.imagePath}" />
</td>
<td class="previousNextCell"
<div class="wisiEntry-nextSampleButton">Next</div>
<div class="wisiEntry-previousSampleButton">Previous</div>
<br />
<div class="wisiEntry-addTagButton">Tag</div>
<div class="wisiEntry-addCommentButton">Comment</div>
<br />
<div class="wisiEntry-uploadButton">Upload</div>
</td>
<td>
<!-- ERROR HAPPENS HERE. Samples should not be null -->
<c:forEach items="${learningEntry.samples}" var="sample" varStatus = "status">
<table class="sampleEntry" ${status.first ? '' : 'style = "display:none"'}>
<tr>
<td class="sampleCell">
<p class="description">
${sample.description}
</p>
<audio src="${sample.audioFileLocation}" controls>
Your browser does not support the <code>audio</code> element.
</audio>
</td>
<td class="voteCell">
<img class="upVote" src="/images/upArrow.jpeg" />
<span class="voteNumber">${sample.votes}</span>
<img class="downVote" src="/images/downArrow.jpeg" />
</td>
</tr>
</table>
</c:forEach>
</td>
</tr>
</table>
</li>
</c:forEach>
</ol><!-- /#posts-list -->
</section><!-- /#content -->

最佳答案

我希望您在调用过程中使用 findAll() 方法。您可以通过修改您的方法来加载所有关联的示例,如下所示。

public List<LearningEntry> findAll() {
List<LearningEntry> entries = jpaTemplate.find("from LearningEntry");
for(LearningEntry entry : entries){
entry.getSamples().size();
}
return entries;
}

或者,正如您所知,您也可以通过将 fetch 更改为 FetchType.EAGER 来实现此目的。但这可能并不适合所有情况。因此,前一种方式更好。

或者您可能不想在任何地方进行任何更改,并定义另一种方法来获取基于 LearningEntry 的所有示例,这样您就可以在某些事件上启动 AJAX 调用。但在这种情况下,这可能不适合。

关于java - Spring 和 Hibernate 的 LazyInitialization 异常,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/2040013/

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