java - 不需要的对象覆盖

Question

我正在尝试编写一个程序来解决逻辑轮难题。我构建了根节点，并尝试生成通过轮子的不同移动而生成的不同子节点。问题是，当我尝试生成子节点时，根节点被覆盖，一切都搞砸了，我真的不知道为什么。 在这里你可以找到拼图logic wheels.

我将轮子表示为 3x3 数组。下面是实现这些 Action 的代码:

public Node turn_right(Node aNode, int which_wheel)
{
    Node newNode = new Node(aNode.getYellow_wheel(),aNode.getBlue_wheel(),aNode.getGreen_wheel());

    int[][] yellow = new int[3][3];
    int[][] blue = new int[3][3];
    int[][] green = new int[3][3];

    if(which_wheel==0) //turn yellow wheel of this node to right
    {
        yellow[1][0] = newNode.getYellow_wheel()[0][0];
        yellow[2][0] = newNode.getYellow_wheel()[1][0];
        yellow[2][1] = newNode.getYellow_wheel()[2][0];
        yellow[2][2] = newNode.getYellow_wheel()[2][1];
        yellow[1][2] = newNode.getYellow_wheel()[2][2];
        yellow[0][2] = newNode.getYellow_wheel()[1][2];
        yellow[0][1] = newNode.getYellow_wheel()[0][2];
        yellow[0][0] = newNode.getYellow_wheel()[0][1];

        blue = newNode.getBlue_wheel();
        blue[1][0] = newNode.getYellow_wheel()[1][2];
        blue[2][0] = newNode.getYellow_wheel()[2][2];

        green = newNode.getGreen_wheel();

    }
    else if(which_wheel == 1)// turn blue wheel of this node to right
    {

        blue[1][0] = newNode.getBlue_wheel()[0][0];
        blue[2][0] = newNode.getBlue_wheel()[1][0];
        blue[2][1] = newNode.getBlue_wheel()[2][0];
        blue[2][2] = newNode.getBlue_wheel()[2][1];
        blue[1][2] = newNode.getBlue_wheel()[2][2];
        blue[0][2] = newNode.getBlue_wheel()[1][2];
        blue[0][1] = newNode.getBlue_wheel()[0][2];
        blue[0][0] = newNode.getBlue_wheel()[0][1];


        yellow = newNode.getYellow_wheel();
        yellow[0][2] = newNode.getBlue_wheel()[0][0];
        yellow[1][2] = newNode.getBlue_wheel()[1][0];

        green = newNode.getGreen_wheel();
        green[1][0] = newNode.getBlue_wheel()[1][2];
        green[2][0] = newNode.getBlue_wheel()[2][2];
    }
    else if (which_wheel == 2)//turn green wheel of this node to right
    {
        green[0][0] = newNode.getGreen_wheel()[0][1];
        green[0][1] = newNode.getGreen_wheel()[0][2];
        green[0][2] = newNode.getGreen_wheel()[1][2];
        green[1][2] = newNode.getGreen_wheel()[2][2];
        green[2][2] = newNode.getGreen_wheel()[2][1];
        green[2][1] = newNode.getGreen_wheel()[2][0];
        green[2][0] = newNode.getGreen_wheel()[1][0];
        green[1][0] = newNode.getGreen_wheel()[0][0];

        yellow = newNode.getYellow_wheel();

        blue = newNode.getBlue_wheel();
        blue[0][2] = newNode.getGreen_wheel()[0][0];
        blue[1][2] = newNode.getGreen_wheel()[1][0];
    }
    newNode= new Node(yellow,blue,green);
    return newNode;
}

还有另一个函数，就像这个函数，它的作用相反:它将轮子向左转动。我的问题是我不希望对象的 aNode 表被覆盖。

非常感谢。

Answer 1

.clone() 复制您不想覆盖的对象。

附:据我了解您的问题，对 blue = newNode.getBlue_wheel(); 的修改也会对 newNode 的蓝色轮子进行更改，是吗？