java Processbuilder - 执行不在 OS X 路径中的文件

Question

好吧，我正在尝试制作 ChucK在导出的处理草图中可用，即如果我从处理导出应用程序，ChucK VM 二进制文件将从应用程序内部执行。因此，作为该应用程序的用户，您根本不需要担心 ChucK 会挡在您的路上。

现在我正在生成并执行一个 bash 脚本文件，但这样我就不会从 ChucK 获得任何控制台输出返回到处理中:

#!/bin/bash
cd "[to where the Chuck executable is located]"
./chuck --kill
killall chuck # just to make sure
./chuck chuckScript1.ck cuckScriptn.ck

然后

Process p = Runtime.getRuntime().exec("chmod 777 "+scriptPath);
p = Runtime.getRuntime().exec(scriptPath);

这可行，但我想直接从处理中运行 ChucK，但无法让它执行:

String chuckPath = "[folder in which the chuck executable is located]"
ProcessBuilder builder = new ProcessBuilder
                              (chuckPath+"/chuck", "test.ck");

        final Process process = builder.start();
        InputStream is = process.getInputStream();
        InputStreamReader isr = new InputStreamReader(is);
        BufferedReader br = new BufferedReader(isr);
        String line;
        while((line = br.readLine()) != null) println(line);
        println("done chuckin'! exitValue: " + process.exitValue());

抱歉，如果这是新手风格:D

Answer 1

ProcessBuilder builder = new ProcessBuilder
                              (chuckPath+"/chuck", chuckPath+"/test.ck");

参数都需要绝对路径。