java - 需要多个 JPanel 来响应其自己的鼠标单击事件

Question

我的应用程序上有多个 JPanel，但是我不知道如何检测到底单击了哪个 JPanel。

在我的 MouseListener 中，我有参数 e，但我的方法不起作用

在代码的早期，我声明了多个 JPanel 和一个监听器对象。

PuzzleListener plist = new PuzzleListener();
JPanel puzzle_board = new JPanel(new GridLayout(4,4,5,5));
...
Square square1 = new Square("1");
Square square2 = new Square("2");
...
puzzle_board.add(square1);
puzzle_board.add(square2);
...
square1.addMouseListener(plist);
square1.addMouseListener(plist);<p></p>

<p>class PuzzleListener implements MouseListener
    {</p>

 public void mouseClicked(MouseEvent e)
 {
       JPanel pnlClick = (JPanel)(e.getSource());
       //System.out.println(pnlClick);
  //System.out.println(e.getSource());
  //System.out.println(e.getComponent().getClass());
  //System.out.println(e.getComponent().getClass().getName());


            //problem is here

  if(pnlClick == square1)
  {
   System.out.println("Panel 1 has been clicked");
  }    
            if(pnlClick == square2)
  {
   System.out.println("Panel 2 has been clicked");
  }       
 }
 public void mouseExited(MouseEvent e)
 {
 }
 public void mouseEntered(MouseEvent e)
 { 
  //System.out.println("Panel 1 has been clicked");
 }
 public void mouseReleased(MouseEvent e)
 {
 }
 public void mousePressed(MouseEvent e)
 {

 }
 /*
 public void actionPerformed(ActionEvent e)
 {
  JPanel pnlClick = (JPanel)(e.getSource());
 }*/

}//end calcListener

Answer 1

问题似乎是您的每个方形面板都有一个类变量和一个局部变量。

Square square1 = new Square("1"); 

应该是:

square1 = new Square("1"); 

现在您将只有一个 PuzzleListener 可以引用的类变量。