java - json 的异常 - JavaME

Question

我正在用java me为黑莓编写一个程序。

无论如何我可以将捕获的java异常写入json格式吗？我怎样才能做到这一点？我应该考虑哪些事情？谢谢!

会这样吗...

catch (IOException e) {
    String IOExceptionMsg = 
        "description:Warn exception: OSError. Exc_type: :Caught IOException:" + 
        e.toString() + ",filename: " + imageName;

    out.write(IOExceptionMsg.getBytes())
} 
catch (Exception e) {
    String Exception = 
        "description: Unknown Error:Caught Exception:" + e.toString() + 
        ",filename:" + imageName;

        out.write(Exception.getBytes());
        out.flush();
}

我有这样的 json 格式..如何将它们放在一起？

`public String toJSON()
{
final String 
IMAGENAME = imageName,
description = "",
filename = imageName;
JSONObject outer = new JSONObject();
JSONObject inner = new JSONObject();
try {
outer.put(IMAGENAME, inner);

// Values are added to the JSONObject in pairs, label then value
inner.put(description, description);
inner.put(filename, imageName);
} catch (JSONException ex) {
ex.printStackTrace();
}
return outer.toString();
        }`

Answer 1

Is there anyway I can write java exception caught into a json format?

您可以捕获异常，然后提取其消息并将其放入 JSON 中以执行您需要的操作，但您不能直接告诉 JVM 将其扔进 JSON 跟踪中。

What about if I have three different types of exceptions? How do I match the filename and the exception?

try{
  //something
}catch(MyExceptionOne ex){
  //do something
}catch(MyExceptionTwo ex){
  //do something different
}catch(MyExceptionThree ex){
  //do something very different
}