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java - 如何在Java Swing中播放mov和wmv视频格式文件?

转载 作者:行者123 更新时间:2023-12-01 15:55:57 25 4
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我正在使用 JMF jar 文件,但我只能听声音但无法观看电影。

  Unable to handle format: RLE , 800x600, FrameRate=14.6, Length=31280
Failed to realize: com.sun.media.PlaybackEngine@17590db
Error: Unable to realize com.sun.media.PlaybackEngine@17590db

我在尝试播放视频时遇到一些错误。

最佳答案

JMF 基本上已死

您可以使用xuggler在java swing中播放wmv文件。

<强> Xuggler is a free open-source library for Java developers to uncompress, manipulate, and compress recorded or live video

You can view the code here

package com.xuggle.xuggler.demos;
import com.xuggle.xuggler.demos.VideoImage;
import javax.sound.sampled.AudioFormat;
import javax.sound.sampled.AudioSystem;
import javax.sound.sampled.DataLine;
import javax.sound.sampled.LineUnavailableException;
import javax.sound.sampled.SourceDataLine;

import com.xuggle.xuggler.IAudioSamples;
import com.xuggle.xuggler.IContainer;
import com.xuggle.xuggler.IPacket;
import com.xuggle.xuggler.IStream;
import com.xuggle.xuggler.IStreamCoder;
import com.xuggle.xuggler.ICodec;


public class DecodeAndPlayAudio
{
private static SourceDataLine mLine;

/**
* Takes a media container (file) as the first argument, opens it,
* opens up the default audio device on your system, and plays back the audio.
*
* @param args Must contain one string which represents a filename
*/
public static void main(String[] args)
{
if (args.length <= 0)
throw new IllegalArgumentException("must pass in a filename as the first argument");

String filename = args[0];

// Create a Xuggler container object
IContainer container = IContainer.make();

// Open up the container
if (container.open(filename, IContainer.Type.READ, null) < 0)
throw new IllegalArgumentException("could not open file: " + filename);

// query how many streams the call to open found
int numStreams = container.getNumStreams();

// and iterate through the streams to find the first audio stream
int audioStreamId = -1;
IStreamCoder audioCoder = null;
for(int i = 0; i < numStreams; i++)
{
// Find the stream object
IStream stream = container.getStream(i);
// Get the pre-configured decoder that can decode this stream;
IStreamCoder coder = stream.getStreamCoder();

if (coder.getCodecType() == ICodec.Type.CODEC_TYPE_AUDIO)
{
audioStreamId = i;
audioCoder = coder;
break;
}
}
if (audioStreamId == -1)
throw new RuntimeException("could not find audio stream in container: "+filename);

/*
* Now we have found the audio stream in this file. Let's open up our decoder so it can
* do work.
*/
if (audioCoder.open() < 0)
throw new RuntimeException("could not open audio decoder for container: "+filename);

/*
* And once we have that, we ask the Java Sound System to get itself ready.
*/
openJavaSound(audioCoder);

/*
* Now, we start walking through the container looking at each packet.
*/
IPacket packet = IPacket.make();
while(container.readNextPacket(packet) >= 0)
{
/*
* Now we have a packet, let's see if it belongs to our audio stream
*/
if (packet.getStreamIndex() == audioStreamId)
{
/*
* We allocate a set of samples with the same number of channels as the
* coder tells us is in this buffer.
*
* We also pass in a buffer size (1024 in our example), although Xuggler
* will probably allocate more space than just the 1024 (it's not important why).
*/
IAudioSamples samples = IAudioSamples.make(1024, audioCoder.getChannels());

/*
* A packet can actually contain multiple sets of samples (or frames of samples
* in audio-decoding speak). So, we may need to call decode audio multiple
* times at different offsets in the packet's data. We capture that here.
*/
int offset = 0;

/*
* Keep going until we've processed all data
*/
while(offset < packet.getSize())
{
int bytesDecoded = audioCoder.decodeAudio(samples, packet, offset);
if (bytesDecoded < 0)
throw new RuntimeException("got error decoding audio in: " + filename);
offset += bytesDecoded;
/*
* Some decoder will consume data in a packet, but will not be able to construct
* a full set of samples yet. Therefore you should always check if you
* got a complete set of samples from the decoder
*/
if (samples.isComplete())
{
playJavaSound(samples);
}
}
}
else
{
/*
* This packet isn't part of our audio stream, so we just silently drop it.
*/
do {} while(false);
}

}
/*
* Technically since we're exiting anyway, these will be cleaned up by
* the garbage collector... but because we're nice people and want
* to be invited places for Christmas, we're going to show how to clean up.
*/
closeJavaSound();

if (audioCoder != null)
{
audioCoder.close();
audioCoder = null;
}
if (container !=null)
{
container.close();
container = null;
}
}

private static void openJavaSound(IStreamCoder aAudioCoder)
{
AudioFormat audioFormat = new AudioFormat(aAudioCoder.getSampleRate(),
(int)IAudioSamples.findSampleBitDepth(aAudioCoder.getSampleFormat()),
aAudioCoder.getChannels(),
true, /* xuggler defaults to signed 16 bit samples */
false);
DataLine.Info info = new DataLine.Info(SourceDataLine.class, audioFormat);
try
{
mLine = (SourceDataLine) AudioSystem.getLine(info);
/**
* if that succeeded, try opening the line.
*/
mLine.open(audioFormat);
/**
* And if that succeed, start the line.
*/
mLine.start();
}
catch (LineUnavailableException e)
{
throw new RuntimeException("could not open audio line");
}

}

 private static void playJavaSound(IAudioSamples aSamples)
{
/**
* We're just going to dump all the samples into the line.
*/
byte[] rawBytes = aSamples.getData().getByteArray(0, aSamples.getSize());
mLine.write(rawBytes, 0, aSamples.getSize());
}

private static void closeJavaSound()
{
if (mLine != null)
{
/*
* Wait for the line to finish playing
*/
mLine.drain();
/*
* Close the line.
*/
mLine.close();
mLine=null;
}
}
}

关于java - 如何在Java Swing中播放mov和wmv视频格式文件?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5048934/

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