javascript - 编译时的 Angular 类型保护错误

Question

我开始一个新的angular项目，但收到以下错误:

ERROR in src/app/app-routing.module.ts(11,5): error TS2740: Type 'typeof LoginGuard' is missing the following properties from type 'any[]': pop, push, concat, join, and 25 more.

typeof 是什么意思loginGuard 实际上是什么意思，我需要做什么才能使其按预期工作？

这是我的路线文件:

import { NgModule } from '@angular/core';
import { Routes, RouterModule } from '@angular/router';
import { LoginComponent } from "./login/login.component";
import { LoginlandingComponent} from "./loginlanding/loginlanding.component";
import { LoginGuard} from "./login.guard";

const routes: Routes = [
  { path: 'login', component: LoginComponent },
  {
    path: '',
    canActivateChild: LoginGuard,
    children: [
      {
        path: 'home',
        component: LoginlandingComponent
      }
    ]
  }

];

@NgModule({
  imports: [RouterModule.forRoot(routes)],
  exports: [RouterModule]
})
export class AppRoutingModule { }

这是我的保护文件:

import { Injectable } from '@angular/core';
import { ActivatedRouteSnapshot, RouterStateSnapshot, UrlTree } from '@angular/router';
import { Observable } from 'rxjs';
import { CanActivate, Router, Route } from '@angular/router';

@Injectable({
  providedIn: 'root'
})
export class LoginGuard implements  CanActivate  {

  constructor(private _router: Router) {
  }

  canActivate(next: ActivatedRouteSnapshot, state: RouterStateSnapshot): Observable<boolean> | Promise<boolean> | boolean {
    if (false) {
      console.log("its true");
      return true;
    }
  console.log("redirecting");
    // navigate to login page
    this._router.navigate(['/login']);
    return false;
  }


}

Answer 1

canActivateChid应该是 array value .
将路由定义更改为:

{
    path: '',
    canActivateChild: [LoginGuard],
    children: [
      {
        path: 'home',
        component: LoginlandingComponent
      }
    ]
  }

另请注意，您正在实现错误的接口(interface)。如果你想为子路由使用那个守卫，你需要实现 CanActivateChild