java - 如何获取特定的请求属性？

Question

所以现在我有代码可以显示来自网址的:

网址:

http://localhost:9080/MyWebApp/MyServlet?qty=1&item=100&desc=CD+ROMS&price=9.99&action=add&addToCart=Add+to+cart

显示内容:

    Recent Queries
    Item_100

下面是显示该内容的代码:

public String getRecentQueries(HttpServletRequest request)
{
    String queries = "";
    HttpSession session = request.getSession(false);
       if (session != null)
       {
          Enumeration e = session.getAttributeNames();
          if ( e.hasMoreElements() )
          {
             queries += "<h4>Recent Queries</h4><ul>";
          }
          while ( e.hasMoreElements() )
          {
             String name = (String) e.nextElement();
             String value =
                (String) session.getAttribute(name);
             queries += "<li><a href=\"" + value + "\">" + 
                name + "</a></li>";
          }
          queries += "</ul></p>";
       }
       return queries;
}

我的问题是，给定网址中的值，我如何获得“item”以外的其他内容？我如何获得 desc 或 price？

Answer 1

试试这个。您需要直接从请求中提取参数名称和值，而不是从 session 中提取属性。

public String getRecentQueries(HttpServletRequest request)
{
    String queries = "";
    Enumeration e = request.getParameterNames();

    if ( e.hasMoreElements() )
    {
        queries += "<h4>Recent Queries</h4><ul>";
    }

    while ( e.hasMoreElements() )
    {
        String name = (String) e.nextElement();
        String value = (String) request.getParameter(name);
        queries += "<li><a href=\"" + value + "\">" + name + "</a></li>";
    }
    queries += "</ul></p>";

    return queries;
}