gpt4 book ai didi

java - XML 到哈希表

转载 作者:行者123 更新时间:2023-12-01 15:51:13 25 4
gpt4 key购买 nike

目前我有下面的代码将数据放入哈希中。我的问题:我必须在 !!!SOMETHING!!! 部分放入哪个值。该代码只需读取一个元素标签并将其值插入到哈希表中。

public void ReadXML(){
try {

DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document doc = builder.parse(fileout);
doc.getDocumentElement().normalize();
Hashtable hash = new Hashtable();

NodeList dataNodes = doc.getElementsByTagName("DataArea");
// getChildNodes().item(0).getChildNodes();
Element root = doc.getDocumentElement();
String dataNodeIndex = root.toString();
System.out.println("");

for (int dataNodeIndex1 = 0; dataNodeIndex1 < dataNodes.getLength(); dataNodeIndex1++)
{
Node nodeName = dataNodes.item(dataNodeIndex1);

if (nodeName.getNodeType() == Node.ELEMENT_NODE) {
Element elementName = (Element) nodeName;
NodeList elementNameList = elementName.getElementsByTagName(elementtag1);
Element elementName2 = (Element) elementNameList.item(0);
NodeList nameElement = elementName2.getChildNodes();
System.out.println("NodeContent: " + ((Node) nameElement.item(0)).getNodeValue());

}
hash.put(elementtag1, !!!SOMETHING!!!);

System.out.println(hash);
}


}



catch(Exception e){
e.printStackTrace();
}


}

最佳答案

你应该使用我发现的这些方法:

protected String getString(String tagName, Element element) {
NodeList list = element.getElementsByTagName(tagName);
if (list != null && list.getLength() > 0) {
NodeList subList = list.item(0).getChildNodes();

if (subList != null && subList.getLength() > 0) {
return subList.item(0).getNodeValue();
}
}

return null;
}

像这样使用它:

if (NodeName.getNodeType() == Node.ELEMENT_NODE) {
Element ElementName = (Element) NodeName;
Hash.put(Elementtag1, getString(Elementtag1, ElementName));

}

检查一下:

http://www.w3.org/TR/2000/REC-DOM-Level-2-Core-20001113/

How to retrieve element value of XML using Java?

关于java - XML 到哈希表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5991800/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com