java - 在 applet-servlet 通信中传输多个参数

Question

我正在实现一个小程序——servlet 通信。 applet 需要向 servlet 发送两个参数。我不确定我可以按照以下方式实现转移过程吗？如果不是，涉及多个参数的传递处理如何处理？谢谢。

小程序端:

// send data to the servlet
             URLConnection con = getServletConnection(hostName);
             OutputStream outstream = con.getOutputStream();
             System.out.println("Send the first parameter");
             ObjectOutputStream oos1 = new ObjectOutputStream(outstream);
             oos1.writeObject(parameter1);
             oos1.flush();
             oos1.close();

             System.out.println("Send the second parameter");
             ObjectOutputStream oos2 = new ObjectOutputStream(outstream);
             oos2.writeObject(parameter2);
             oos2.flush();
             oos2.close();

Servlet 端:

    InputStream in1 = request.getInputStream();
    ObjectInputStream inputFromApplet = new ObjectInputStream(in1);
    String receievedData1 = (String)inputFromApplet.readObject();

    InputStream in2 = request.getInputStream();
    ObjectInputStream inputFromApplet = new ObjectInputStream(in2);
    String receievedData2 = (String)inputFromApplet.readObject();

Answer 1

为简单起见，您应该使用 HTTP GET 或 POST 参数(因为它们是字符串值)。

小程序端:

URL postURL = new URL("http://"+host+"/ServletPath");
HttpURLConnection conn = (HttpURLConnection) postURL.openConnection();
conn.setRequestMethod("POST");
conn.setDoOutput(true);
conn.connect();

PrintWriter out = new PrintWriter(conn.getOutputStream());
out.write("param1="+URLEncoder.encode(parameter1)+"&param2="+URLEncoder.encode(parameter2));
out.flush();

可以通过 Applet 实例中的 getCodeBase().getHost() 获取主机。

Servlet 端:

void doPost(HttpServletRequest req, HttpServletResponse resp) {
    String parameter1 = req.getParameter("param1");
    String parameter2 = req.getParameter("param2");
}