javascript - Array.prototype.map() 函数与 JS 对象的行为

Question

我正在尝试以下代码:

 let obj ={};
    let newIngredients = ["Hello", "Distraction", "Nothing", "Love"].map(el => {
        obj.count= Math.random()*el.length;
        obj.ingredient= el;
        return obj;
    });
    console.log(newIngredients);

这是我得到的输出:

(4) [{…}, {…}, {…}, {…}]
0: {count: 1.4648989727265578, ingredient: "Love"}
1: {count: 1.4648989727265578, ingredient: "Love"}
2: {count: 1.4648989727265578, ingredient: "Love"}
3: {count: 1.4648989727265578, ingredient: "Love"}
length: 4
__proto__: Array(0)

这不是我想要的。但是当我输入以下内容时，

let obj;
let newIngredients = ["Hello", "Distraction", "Nothing", "Love"].map(el => {
      obj = {
               count: Math.random()*el.length,
               ingredient: el
            } ;
      return obj;
 });
 console.log(newIngredients);

它返回以下输出，这是我真正想要的:

(4) [{…}, {…}, {…}, {…}]
0: {count: 4.2813861024052615, ingredient: "Hello"}
1: {count: 5.850654082147917, ingredient: "Distraction"}
2: {count: 6.646446034466489, ingredient: "Nothing"}
3: {count: 1.7062874250924214, ingredient: "Love"}
length: 4
__proto__: Array(0)

谁能解释为什么这两个代码片段之间的行为存在差异？

Answer 1

在您的第一个示例中，您只创建了一个对象，然后将它放入数组中四次:

let obj ={}; // <===== Creates the one object
let newIngredients = ["Hello", "Distraction", "Nothing", "Love"].map(el => {
    obj.count= Math.random()*el.length;
    obj.ingredient= el;
    return obj; // <===== Puts it in the array four times
});
console.log(newIngredients);

因为只有一个对象，所以每次执行 obj.ingredient = el; 时，您都更新了属性，替换了它之前的值。

结果在内存中看起来是这样的:

                                            +−−−−−−−−−−−−−−−−−−−−−−−−−−−+obj:Ref11654−−−−−−−−−−−−−−−−−−−−−−−+−+−+−+−>|         (object)          |                                  / / / /   +−−−−−−−−−−−−−−−−−−−−−−−−−−−+                                  | | | |   | count: 1.4648989727265578 |                                  | | | |   | ingredient: "Love"        |                                  | | | |   +−−−−−−−−−−−−−−−−−−−−−−−−−−−+                                  | | | |                  +−−−−−−−−−−−−−+ | | | |newIngredients−−−>|   (array)   | | | | |                  +−−−−−−−−−−−−−+ | | | |                  | 0: Ref11654 |−+ | | |                  | 1: Ref11654 |−−−+ | |                  | 2: Ref11654 |−−−−−+ |                  | 3: Ref11654 |−−−−−−−+                  +−−−−−−−−−−−−−+

It's exactly like doing this:

let first = {};
first.a = 1;
let second = first;
second.a = 2;
console.log(first.a); // 2, not 1

您的第二个示例为每次调用 map 回调创建了一个对象，这是正确的，尽管不需要 obj 变量并且拥有它有点误导.所以:

let newIngredients = ["Hello", "Distraction", "Nothing", "Love"].map(el => {
    return {
        count: Math.random()*el.length,
        ingredient: el
    };
});
console.log(newIngredients);

或者用一个简洁的箭头函数:

let newIngredients = ["Hello", "Distraction", "Nothing", "Love"].map(el => ({
    count: Math.random()*el.length,
    ingredient: el
}));
console.log(newIngredients);