python - 创建一个简单的 HTTP python 服务器来处理损坏的管道

Question

我创建了一个简单的 python http 服务器，我希望它只显示我想要的目录中的文件，从而改变总是返回“Hello world!”以及如何处理损坏的管道错误？我试着做一个 try catch在那里，但我不确定它是否有效:

#!/usr/bin/python
from BaseHTTPServer import BaseHTTPRequestHandler,HTTPServer

PORT_NUMBER = 8089

#This class will handles any incoming request from
#the browser 
class myHandler(BaseHTTPRequestHandler):

    #Handler for the GET requests
    def do_GET(self):
        self.send_response(200)
        self.send_header('Content-type','text/html')
        self.end_headers()
        self.wfile.write("Hello World !")
        return

try:
    #Create a web server and define the handler to manage the
    #incoming request
    server = HTTPServer(('', PORT_NUMBER), myHandler)
    print 'Started http server on port ' , PORT_NUMBER

    #Wait forever for incoming http requests
    server.serve_forever()

except KeyboardInterrupt:
    print '^C received, shutting down the web server'
    server.socket.close()
except socket.error:
    pass

这是我的错误:

someIP - - [25/Dec/2019 09:17:11] "GET someFILE HTTP/1.0" 200 -
Traceback (most recent call last):
  File "/usr/lib/python2.7/SocketServer.py", line 293, in _handle_request_noblock
    self.process_request(request, client_address)
  File "/usr/lib/python2.7/SocketServer.py", line 321, in process_request
    self.finish_request(request, client_address)
  File "/usr/lib/python2.7/SocketServer.py", line 334, in finish_request
    self.RequestHandlerClass(request, client_address, self)
  File "/usr/lib/python2.7/SocketServer.py", line 657, in __init__
    self.finish()
  File "/usr/lib/python2.7/SocketServer.py", line 716, in finish
    self.wfile.close()
  File "/usr/lib/python2.7/socket.py", line 283, in close
    self.flush()
  File "/usr/lib/python2.7/socket.py", line 307, in flush
    self._sock.sendall(view[write_offset:write_offset+buffer_size])
error: [Errno 32] Broken pipe

Answer 1

下面的示例是创建用于静态文件服务的基本 Web 服务器的基本示例。您可以在代码中找到其他注释，并附上一个附加说明:403 Forbidden implementation can be replace with file indexing page, for you need to do the additional generation of it(根据您的问题，这现在超出了范围。 )

from http.server import HTTPServer, BaseHTTPRequestHandler
from os import curdir, sep, path


class SimpleHTTPRequestHandler(BaseHTTPRequestHandler):

    def do_GET(self):
        self.send_response(200) #Request received, sending OK status
        self.end_headers()
        try:
            if(path.isdir(self.path)): #Checking if user requested access to dirrectory (not to a particular file)
                self.send_response(403)
                self.wfile.write(str.encode("Listing of directories not permited on this server")) #Preventing directory listing, in case you dont want to allow file indexing.
            else: #If user is requesting access to a file, file content is read and displayed.
                f = open(curdir + sep + self.path, 'rb')
                self.wfile.write(f.read())
                f.close()
        except IOError: #Covering the 404 error, in case user requested non-existing file
            print("File "+self.path+" not found")
            self.send_response(404)


httpd = HTTPServer(('localhost', 8000), SimpleHTTPRequestHandler)
httpd.serve_forever()