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我有一个返回 JSON 的 REST Web 服务。作为示例,我有以下响应:
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现在我想使用 GSON 将其转换为 POJO 对象。对于顶部根节点,我创建了以下类:
public class JSONContainer {
ArrayList<JSONWorkItem> items = new ArrayList<JSONWorkItem>();
public ArrayList<JSONWorkItem> getItems() {
return items;
}
}
这不起作用,因为我认为 ArrayList 应该名为 oslc_cm:results,但我不能,因为这不是有效的 Java 标识符。那我能做什么呢?
最佳答案
答案可以在 Gson User Guide 中找到。 。您可以使用注释 SerializedName 来实现此目的。
所以 POJO 类应该如下所示:
public class JSONContainer {
@SerializedName("oslc_cm:results")
ArrayList<JSONWorkItem> items = new ArrayList<JSONWorkItem>();
public ArrayList<JSONWorkItem> getItems() {
return items;
}
}
关于java - 如何使用 Google 的 GSON 解析 JSON 无效标识符?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8282403/
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