java - 如何处理InputMismatchException？

Question

这是 Bruce Eckel Thinking in Java，第四版的示例

import java.io.BufferedReader;
import java.io.StringReader;
import java.util.Scanner;

public class BetterRead {
  public static void main(String[] args) {
    BufferedReader input = new BufferedReader(new StringReader("Sir Robin of Camelot\n22 1.61803"));
    Scanner stdin = new Scanner(input);
    System.out.println("What is your name?");
    String name = stdin.nextLine();
    System.out.println(name);
    System.out.println("How old are you? What is your favorite double?");
    System.out.println("(input: <age> <double>)");
    int age = stdin.nextInt();
    double favorite = stdin.nextDouble();
    System.out.println(age);
    System.out.println(favorite);
    System.out.format("Hi %s.\n", name);
    System.out.format("In 5 years you will be %d.\n",
      age + 5);
    System.out.format("My favorite double is %f.",
      favorite / 2);
  }
}

这里是输出

 What is your name?
Sir Robin of Camelot
How old are you? What is your favorite double?
(input: <age> <double>)
Exception in thread "main" java.util.InputMismatchException
    at java.util.Scanner.throwFor(Scanner.java:909)
    at java.util.Scanner.next(Scanner.java:1530)
    at java.util.Scanner.nextFloat(Scanner.java:2388)
    at betterread.BetterRead.main(BetterRead.java:21)
Java Result: 1

我对 Java 还很陌生，但正如您在本例中看到的，int 跟在 buy double 后面。所以它可能工作正常。但仍然抛出InputMismatchException。如何解决这个问题？

Answer 1

问题似乎出在您的区域设置上，因为 1.61803 似乎不是它的有效 double 值。尝试使用 1,61803。