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reactjs - 如何在redux中过滤和排序相同的对象状态数组?

转载 作者:行者123 更新时间:2023-12-01 15:33:10 25 4
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我正在开发电影收藏应用程序,其中有一个包含电影列表的页面。我想添加根据年份、流派和评级过滤电影的功能,并且我想按字母顺序、年份和评级对其进行排序。我如何通过使用 redux 来实现这一点,并通过使用单个状态对象使用react。

最佳答案

首先,我们应该创建组件来显示电影列表。
注意,这是一个纯粹的无状态组件,我们不会在那里进行排序或过滤,只是渲染派生的 props:

// Movies.js

import React from 'react';

function Movies({ movies }) {
return (
<ul>
{movies.map((m, i) =>
<li key={i}>{m.year} - {m.title}.({m.genre}) - {m.rating}</li>
)}
</ul>
);
}

export default Movies;

接下来我们将创建另一个无状态组件,它将包含排序和过滤 View 。这里我们也渲染 Prop ,并提供对 select 的回调。元素:

// Pane.js

import React from 'react';

function Pane({
selectedYear,
selectedGenre,
selectedRating,
years = [],
genres = [],
ratings = [],
sorting,
onYearChange,
onGenreChange,
onRatingChange,
onSortingChange,
}) {
return (
<div>
<div>
Filters:
<div>
Year:
<select
defaultValue={selectedYear}
onChange={e => onYearChange(e.target.value)}
>
<option value="all" >All</option>
{years.map((y, i) =>
<option key={i} value={y}>{y}</option>
)}
</select>
</div>
<div>
Genre:
<select
defaultValue={selectedGenre}
onChange={e => onGenreChange(e.target.value)}
>
<option value="all" >All</option>
{genres.map((g, i) =>
<option key={i} value={g}>{g}</option>
)}
</select>
</div>
<div>
Rating:
<select
defaultValue={selectedRating}
onChange={e => onRatingChange(e.target.value)}
>
<option value="all" >All</option>
{ratings.map((r, i) =>
<option key={i} value={r}>{r}</option>
)}
</select>
</div>
</div>
<div>
Select sorting:
<select
defaultValue={sorting}
onChange={e => onSortingChange(e.target.value)}
>
<option value="alphabetically">Alphabetically</option>
<option value="year">Year</option>
<option value="rating">Rating</option>
</select>
</div>
</div>
);
}

export default Pane;

我们将在应用程序状态中存储电影和所有过滤和排序数据。
我们需要创建reducer,来处理排序和过滤操作:

// reducers.js

const items = [{
title: 'Mad max',
year: 2015,
rating: 8,
genre: 'fantasy',
}, {
title: 'Spider man 2',
year: 2014,
rating: 7,
genre: 'fantasy',
}, {
title: 'Iron man 3',
year: 2013,
rating: 7,
genre: 'fantasy',
}, {
title: 'Dumb and Dumber To',
year: 2014,
rating: 5,
genre: 'comedy',
}, {
title: 'Ted 2',
year: 2015,
rating: 6,
genre: 'comedy',
}];

export default function moviesReducer(state = {
movies: items,
year: 'all',
rating: 'all',
genre: 'all',
sorting: 'year',
}, action) {
switch (action.type) {
case 'SET_YEAR':
return {
...state,
year: action.year,
};
case 'SET_RATING':
return {
...state,
rating: action.rating,
};
case 'SET_GENRE':
return {
...state,
genre: action.genre,
};
case 'SET_SORTING':
return {
...state,
sorting: action.sorting,
};
default:
return state;
}
}

为了向无状态组件提供数据,我们应该使用 containers .让我们创建 PaneContainerPane 提供排序和过滤数据成分:

// PaneContainer.js

import { connect } from 'react-redux';
import Pane from './Pane';

// Simple helper function, which return all filters from state by given key.
function getFilters(key, movies) {
return movies.reduce((acc, movie) => {
if (!acc.includes(movie[key])) {
return [...acc, movie[key]];
}
return acc;
}, []);
}

function mapStateToProps(state, props) {
const { sorting, year, genre, rating } = state;
return {
selectedYear: year,
selectedGenre: genre,
selectedRating: rating,
years: getFilters('year', state.movies),
genres: getFilters('genre', state.movies),
ratings: getFilters('rating', state.movies),
sorting,
};
}

function mapDispatchToProps(dispatch, props) {
return {
// Here, we are providing callbacks with dispatching functions.
onYearChange(year) {
dispatch({
type: 'SET_YEAR',
year,
});
},
onGenreChange(genre) {
dispatch({
type: 'SET_GENRE',
genre,
});
},
onRatingChange(rating) {
dispatch({
type: 'SET_RATING',
rating,
});
},
onSortingChange(sorting) {
dispatch({
type: 'SET_SORTING',
sorting,
});
},
};
}

export default connect(
mapStateToProps,
mapDispatchToProps
)(Pane);

最后,我们将创建 MoviesContainer它将向 Movies 提供可见的电影成分:

// MoviesContainer.js

import { connect } from 'react-redux';
import Movies from './Movies';

// Getting visible movies from state.
function getVisibleMovies(year, genre, rating, sorting, movies) {
return movies
.filter(m => {
return (
(year == 'all' || year == m.year) &&
(genre == 'all' || genre == m.genre) &&
(rating == 'all' || rating == m.rating)
);
})
.sort((a, b) => {
if (sorting == 'year') {
return b.year - a.year;
}
if (sorting == 'rating') {
return b.rating - a.rating;
}
if (sorting == 'alphabetically') {
return a.title > b.title ? 1 : a.title < b.title ? -1 : 0;
}
});
}

function mapStateToProps(state) {
const { year, genre, rating, sorting, movies } = state;
return {
movies: getVisibleMovies(year, genre, rating, sorting, movies),
};
}

export default connect(mapStateToProps)(Movies);

关于reactjs - 如何在redux中过滤和排序相同的对象状态数组?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38133137/

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