java - 将多个字符串组合成一个字符串，然后可以将其分离为原始字符串的智能方法？

Question

假设各个字符串中可以使用的字符没有限制，并且字符串可能为空。

编辑:

似乎执行此操作的正确方法是使用分隔符，并转义任何单个字符串中已存在的分隔符。以下是我对此的尝试，它似乎有效。是否错过了任何会破坏它的情况？:

public static void main(String args[])
{
    Vector<String> strings = new Vector<String>();
    strings.add("abab;jmma");
    strings.add("defgh;,;");
    strings.add("d;;efgh;,;");
    strings.add("");
    strings.add("");
    strings.add(";;");
    strings.add(";,;");


    String string = combine(strings);
    strings= separate(string);
    System.out.println();
}

static String combine(Vector<String> strings)
{
    StringBuilder builder = new StringBuilder();

    for(String string : strings)
    {
        //don't prepend a SEPARATOR to the first string
        if(!builder.toString().equals(""))
        {
            builder.append(";");
        }

        string = string.replaceAll(";", ",;");

        builder.append(string);
    }

    return builder.toString();
}

static Vector<String> separate(String string)
{
    Vector<String> strings = new Vector<String>();

    separate(string, strings, 0);

    return strings;
}

static void separate(String string, Vector<String> strings, int currIndex)
{
    int nextIndex = -1;
    int checkIndex = currIndex;

    while(nextIndex == -1 && checkIndex < string.length())
    {
        nextIndex = string.indexOf(';', checkIndex);
        //look back to determine if this occurance is escaped
        if(string.charAt(nextIndex - 1) == ',')
        {
            //this ones is escaped, doesn't count
            checkIndex = nextIndex + 1;
            nextIndex = -1;

        }
    }

    if(nextIndex == -1)
    {
        //no more remain  

        String toAdd = string.substring(currIndex, string.length());
        toAdd = toAdd.replaceAll(",;", ";");
        strings.add(toAdd);
        return;
    }
    else if(currIndex + 1 == nextIndex)
    {
        //empty string 

        strings.add("");
        separate(string, strings, nextIndex);
    }
    else
    {
        //there could be more

        String toAdd = string.substring(currIndex, nextIndex);
        toAdd = toAdd.replaceAll(",;", ";");
        strings.add(toAdd);
        separate(string, strings, nextIndex + 1);
    }
}

}

Answer 1

获取字符串 vector 并将其转换为 JSON 对象并存储该 JSON 对象。

( http://www.json.org/ 和 http://www.json.org/java/ )