gpt4 book ai didi

ios - 如何在 SwiftUI 列表/ForEach 中动态创建部分并避免 "Unable to infer complex closure return type"

转载 作者:行者123 更新时间:2023-12-01 15:24:26 25 4
gpt4 key购买 nike

我正在尝试重新创建与股票 iOS 日历应用程序中的事件列表匹配的 View 。我有以下代码,它生成一个事件列表,每个事件按日期分为自己的部分:

var body: some View {
NavigationView {
List {
ForEach(userData.occurrences) { occurrence in
Section(header: Text("\(occurrence.start, formatter: Self.dateFormatter)")) {
NavigationLink(
destination: OccurrenceDetail(occurrence: occurrence)
.environmentObject(self.userData)
) {
OccurrenceRow(occurrence: occurrence)
}
}
}
}
.navigationBarTitle(Text("Events"))
}.onAppear(perform: populate)
}

这段代码的问题在于,如果同一日期有两个事件,它们会被分成具有相同标题的不同部分,而不是被组合到同一个部分中。

作为一个 Swift 新手,我的直觉是做这样的事情:
ForEach(userData.occurrences) { occurrence in
if occurrence.start != self.date {
Section(header: Text("\(occurrence.start, formatter: Self.dateFormatter)")) {
NavigationLink(
destination: OccurrenceDetail(occurrence: occurrence)
.environmentObject(self.userData)
) {
OccurrenceRow(occurrence: occurrence)
}
}
} else {
NavigationLink(
destination: OccurrenceDetail(occurrence: occurrence)
.environmentObject(self.userData)
) {
OccurrenceRow(occurrence: occurrence)
}
}
self.date = occurrence.start

但是在 Swift 中,这给了我错误“无法推断复杂的闭包返回类型;添加显式类型以消除歧义”,因为我在 ForEach{} 中调用任意代码 (self.date =occurrence.start),这是不允许的.

实现这一点的正确方法是什么?有没有更动态的方法来执行它,还是我需要以某种方式抽象 ForEach{} 之外的代码?

编辑: Occurrence 对象如下所示:
struct Occurrence: Hashable, Codable, Identifiable {
var id: Int
var title: String
var description: String
var location: String
var start: Date
var end: String
var cancelled: Bool
var public_occurrence: Bool
var created: String
var last_updated: String

private enum CodingKeys : String, CodingKey {
case id, title, description, location, start, end, cancelled, public_occurrence = "public", created, last_updated
}
}

更新:
以下代码为我提供了一个字典,其中包含由同一日期键入的事件数组:
let myDict = Dictionary( grouping: value ?? [], by: { occurrence -> String in
let dateFormatter = DateFormatter()
dateFormatter.dateStyle = .medium
dateFormatter.timeStyle = .none
return dateFormatter.string(from: occurrence.start)
})
self.userData.latestOccurrences = myDict

但是,如果我尝试在我的 View 中使用它,如下所示:
ForEach(self.occurrencesByDate) { occurrenceSameDate in
// Section(header: Text("\(occurrenceSameDate[0].start, formatter: Self.dateFormatter)")) {
ForEach(occurrenceSameDate, id: occurrenceSameDate.id){ occurrence in
NavigationLink(
destination: OccurrenceDetail(occurrence: occurrence)
.environmentObject(self.userData)
) {
OccurrenceRow(occurrence: occurrence)
}
}
// }
}

(当我得到主要部分工作时,部分内容被注释掉了)

我收到此错误:无法将类型“_.Element”的值转换为预期的参数类型“发生”

最佳答案

引用我对您问题的评论,数据应在显示之前放入部分中。

这个想法是有一个对象数组,其中每个对象都包含一个事件数组。因此,我们简化了您的发生对象(对于此示例)并创建以下内容:

struct Occurrence: Identifiable {
let id = UUID()
let start: Date
let title: String
}

接下来,我们需要一个对象来表示给定日期发生的所有事件。我们称之为 Day对象,但是对于这个例子来说,名字并不是很重要。
struct Day: Identifiable {
let id = UUID()
let title: String
let occurrences: [Occurrence]
let date: Date
}

所以我们要做的是取一个数组 Occurrence对象并将它们转换为 Day 的数组对象。

我创建了一个简单的结构来执行实现这一目标所需的所有任务。显然你会想要修改它,使它与你拥有的数据相匹配,但关键是你将拥有一个 Day 的数组。然后可以轻松显示的对象。我已经通过代码添加了注释,以便您可以清楚地看到每件事在做什么。
struct EventData {
let sections: [Day]

init() {
// create some events
let first = Occurrence(start: EventData.constructDate(day: 5, month: 5, year: 2019), title: "First Event")
let second = Occurrence(start: EventData.constructDate(day: 5, month: 5, year: 2019, hour: 10), title: "Second Event")
let third = Occurrence(start: EventData.constructDate(day: 5, month: 6, year: 2019), title: "Third Event")

// Create an array of the occurrence objects and then sort them
// this makes sure that they are in ascending date order
let events = [third, first, second].sorted { $0.start < $1.start }

// create a DateFormatter
let dateFormatter = DateFormatter()
dateFormatter.dateStyle = .medium
dateFormatter.timeStyle = .none

// We use the Dictionary(grouping:) function so that all the events are
// group together, one downside of this is that the Dictionary keys may
// not be in order that we require, but we can fix that
let grouped = Dictionary(grouping: events) { (occurrence: Occurrence) -> String in
dateFormatter.string(from: occurrence.start)
}

// We now map over the dictionary and create our Day objects
// making sure to sort them on the date of the first object in the occurrences array
// You may want a protection for the date value but it would be
// unlikely that the occurrences array would be empty (but you never know)
// Then we want to sort them so that they are in the correct order
self.sections = grouped.map { day -> Day in
Day(title: day.key, occurrences: day.value, date: day.value[0].start)
}.sorted { $0.date < $1.date }
}

/// This is a helper function to quickly create dates so that this code will work. You probably don't need this in your code.
static func constructDate(day: Int, month: Int, year: Int, hour: Int = 0, minute: Int = 0) -> Date {
var dateComponents = DateComponents()
dateComponents.year = year
dateComponents.month = month
dateComponents.day = day
dateComponents.timeZone = TimeZone(abbreviation: "GMT")
dateComponents.hour = hour
dateComponents.minute = minute

// Create date from components
let userCalendar = Calendar.current // user calendar
let someDateTime = userCalendar.date(from: dateComponents)
return someDateTime!
}

}

这将允许 ContentView简单地成为两个嵌套 ForEach .
struct ContentView: View {

// this mocks your data
let events = EventData()

var body: some View {
NavigationView {
List {
ForEach(events.sections) { section in
Section(header: Text(section.title)) {
ForEach(section.occurrences) { occurrence in
NavigationLink(destination: OccurrenceDetail(occurrence: occurrence)) {
OccurrenceRow(occurrence: occurrence)
}
}
}
}
}.navigationBarTitle(Text("Events"))
}
}
}

// These are sample views so that the code will work
struct OccurrenceDetail: View {
let occurrence: Occurrence

var body: some View {
Text(occurrence.title)
}
}

struct OccurrenceRow: View {
let occurrence: Occurrence

var body: some View {
Text(occurrence.title)
}
}

这是最终结果。

Nested Views

关于ios - 如何在 SwiftUI 列表/ForEach 中动态创建部分并避免 "Unable to infer complex closure return type",我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58574847/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com