javascript - 我想提取重复项中的最大值

Question

我想删除重复的值，但我想选择长度最大值的那个。

let meary = [];
meary.push({ name: "aaa", value: 90, length: 3 });
meary.push({ name: "bbb", value: 90, length: 5 });
meary.push({ name: "ccc", value: 80, length: 3 });
meary.push({ name: "ddd", value: 0, length: 4 });
meary.push({ name: "eee", value: 0, length: 3 });
meary = meary.filter((ele, index, arr) => {
  // 重複削除
  const isa =
    arr.findIndex((item) => {
      if (item.value === ele.value) {
        if (item.length > ele.length) {
          return true;
        }
      }
      return false;
    }) === index;
  return isa;
});
console.log(JSON.stringify(meary));

这是我想要的结果

[
  { name: "bbb", value: 90, length: 5 },
  { name: "ccc", value: 80, length: 3 },
  { name: "ddd", value: 0, length: 4 }
]

这是得到的实际结果

[]

如何编写代码以获得我想要的结果？

Answer 1

你可以filter排除那些具有相同值且长度小于 some 的项目数组中的其他项:

const meary = [];
meary.push({ name: "aaa", value: 90, length: 3 });
meary.push({ name: "bbb", value: 90, length: 5 });
meary.push({ name: "ccc", value: 80, length: 3 });
meary.push({ name: "ddd", value: 0, length: 4 });
meary.push({ name: "eee", value: 0, length: 3 });

const result = meary.filter(
  (x, i, a) => !a.some(
    (y, j) => x.value === y.value && x.length < y.length && i != j
  )
);

console.log(result);