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java - REST Web 服务 - 示例代码 - 提供 HTTP 302 响应

转载 作者:行者123 更新时间:2023-12-01 15:22:45 25 4
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我只是在尝试 REST Web 服务;标准 sample ;虽然我能够创建 war 并将其加载到 WSO2 AS 中,但当我尝试将其与客户端连接时,我收到 HTTP 302 的响应;我想知道错误可能出在哪里;以下是我的文件列表。

package com.indu.rs.test;

import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;

// POJO, no interface no extends

// The class registers its methods for the HTTP GET request using the @GET annotation.
// Using the @Produces annotation, it defines that it can deliver several MIME types,
// text, XML and HTML.

// The browser requests per default the HTML MIME type.

//Sets the path to base URL + /hello
@Path("/hello")
public class Hello {

// This method is called if TEXT_PLAIN is request
@GET
@Produces(MediaType.TEXT_PLAIN)
public String sayPlainTextHello() {
return "Hello Jersey";
}

// This method is called if XML is request
@GET
@Produces(MediaType.TEXT_XML)
public String sayXMLHello() {
return "<?xml version=\"1.0\"?>" + "<hello> Hello Jersey" + "</hello>";
}

// This method is called if HTML is request
@GET
@Produces(MediaType.TEXT_HTML)
public String sayHtmlHello() {
return "<html> " + "<title>" + "Hello Jersey" + "</title>"
+ "<body><h1>" + "Hello Jersey" + "</h1></body>" + "</html> ";
}

} // class

web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">

<display-name>com.indu.rs.test</display-name>

<servlet>
<servlet-name>Jersey1</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>com.indu.rs.test</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
<servlet-name>Jersey1</servlet-name>
<url-pattern>/rest</url-pattern>
</servlet-mapping>
</web-app>

客户端

package com.indu.rs.test.client;

import java.net.URI;

import javax.ws.rs.core.MediaType;
import javax.ws.rs.core.UriBuilder;

import com.sun.jersey.api.client.Client;
import com.sun.jersey.api.client.ClientResponse;
import com.sun.jersey.api.client.WebResource;
import com.sun.jersey.api.client.config.ClientConfig;
import com.sun.jersey.api.client.config.DefaultClientConfig;

public class RsTest {
public static void main(String[] args) {
ClientConfig config = new DefaultClientConfig();
Client client = Client.create(config);
WebResource service = client.resource(getBaseURI());

// Fluent interfaces
System.out.println(service.path("rest").path("hello").accept(
MediaType.TEXT_PLAIN).get(ClientResponse.class).toString());

// Get plain text
System.out.println(service.path("rest").path("hello").accept(
MediaType.TEXT_PLAIN).get(String.class));

// Get XML
System.out.println(service.path("rest").path("hello").accept(
MediaType.TEXT_XML).get(String.class));

// The HTML
System.out.println(service.path("rest").path("hello").accept(
MediaType.TEXT_HTML).get(String.class));


}

private static URI getBaseURI() {
return UriBuilder.fromUri(
"http://localhost:9100/com.indu.rs.test").build();
}

}

最佳答案

302 表示您正在被重定向。使用curl --verbose 连接到端点,并查看Location: header 。它应该可以让您了解正在发生的事情。

关于java - REST Web 服务 - 示例代码 - 提供 HTTP 302 响应,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10646825/

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