java - 当我从 android ADB 调用我的网络服务时，10.0.2.2 中存在非法字符

Question

我使用 netbeans (Java EE) 制作了一个 Web 服务，并且我想与我的 Android 应用程序(使用 Eclipse 制作)进行通信。

例如，当我尝试通信时，我通过浏览器调用我的网络服务:

localhost:9999/SupRails_Start/resources/rest/mail@gmail.com/password

...它给了我一个 JSON，...

对于 ADB，我将其称为 URI:

10.0.2.2:9999/SupRails_Start/resources/rest/mail@gmail.com/password

但它给了我

java.lang.IllegalArgumentException: Illegal character in scheme at index 0: 10.0.2.2:0000/SupRails_Start/resources/rest/...

当我将 JSON(从浏览器接收到)复制粘贴到 php 页面并将其托管在网络上时，它运行得很好!

这是我的 Android 项目的一部分:

WebService webService = new WebService("10.0.2.2:9999/SupRails_Start/resources/rest/wil.nad@gmail.com/root");
        Map<String, String> params = new HashMap<String, String>();
        String temp = webService.webGet("", params);
        Log.v("", "JSON received = "+temp);

请帮助我，我不明白我的错误...非常感谢!

Answer 1

您的网络服务 URL 不完整。有效 URL 的语法如下:

scheme://domain:port/path?query_string#fragment_id

Every URL consists of some of the following: the scheme name (commonly called protocol), followed by a colon, two slashes,[note 1] then, depending on scheme, a server name (exp. ftp., www., smtp., etc) followed by a dot (.) then a domain name[note 2] (alternatively, IP address), a port number, the path of the resource to be fetched or the program to be run, then, for programs such as Common Gateway Interface (CGI) scripts, a query string,[7][8] and an optional fragment identifier.

[Wikipedia]

所以改变这个:

new WebService("10.0.2.2:9999/SupRails_Start/resources/rest/wil.nad@gmail.com/root")

对此:

new WebService("http://10.0.2.2:9999/SupRails_Start/resources/rest/wil.nad@gmail.com/root")