python - Scrapy 使用 crawlerprocess 运行时抛出错误

Question

我在 python 中编写了一个脚本，使用 scrapy 从网站收集不同帖子的名称及其链接。当我从命令行执行我的脚本时，它可以完美运行。现在，我的意图是使用 CrawlerProcess() 运行脚本.我在不同的地方寻找类似的问题，但我找不到任何直接的解决方案或任何更接近的解决方案。但是，当我尝试按原样运行它时，出现以下错误:

from stackoverflow.items import StackoverflowItem ModuleNotFoundError: No module named 'stackoverflow'

到目前为止，这是我的脚本( stackoverflowspider.py):

from scrapy.crawler import CrawlerProcess
from stackoverflow.items import StackoverflowItem
from scrapy import Selector
import scrapy

class stackoverflowspider(scrapy.Spider):
    name = 'stackoverflow'
    start_urls = ['https://stackoverflow.com/questions/tagged/web-scraping']

    def parse(self,response):
        sel = Selector(response)
        items = []
        for link in sel.xpath("//*[@class='question-hyperlink']"):
            item = StackoverflowItem()
            item['name'] = link.xpath('.//text()').extract_first()
            item['url'] = link.xpath('.//@href').extract_first()
            items.append(item)
        return items

if __name__ == "__main__":
    c = CrawlerProcess({
        'USER_AGENT': 'Mozilla/5.0',   
    })
    c.crawl(stackoverflowspider)
    c.start()

items.py包括:

import scrapy

class StackoverflowItem(scrapy.Item):
    name = scrapy.Field()
    url = scrapy.Field()

这是树:
Click to see the hierarchy

I know I can bring up success this way but I am only interested to accomplish the task with the way I tried above:

def parse(self,response):
    for link in sel.xpath("//*[@class='question-hyperlink']"):
        name = link.xpath('.//text()').extract_first()
        url = link.xpath('.//@href').extract_first()
        yield {"Name":name,"Link":url}

Answer 1

尽管@Dan-Dev 向我展示了正确方向的方法，但我决定提供一个完美无瑕的完整解决方案。
除了我在下面粘贴的内容之外，什么都没有改变:

import sys
#The following line (which leads to the folder containing "scrapy.cfg") fixed the problem
sys.path.append(r'C:\Users\WCS\Desktop\stackoverflow')
from scrapy.crawler import CrawlerProcess
from stackoverflow.items import StackoverflowItem
from scrapy import Selector
import scrapy


class stackoverflowspider(scrapy.Spider):
    name = 'stackoverflow'
    start_urls = ['https://stackoverflow.com/questions/tagged/web-scraping']

    def parse(self,response):
        sel = Selector(response)
        items = []
        for link in sel.xpath("//*[@class='question-hyperlink']"):
            item = StackoverflowItem()
            item['name'] = link.xpath('.//text()').extract_first()
            item['url'] = link.xpath('.//@href').extract_first()
            items.append(item)
        return items

if __name__ == "__main__":
    c = CrawlerProcess({
        'USER_AGENT': 'Mozilla/5.0',   
    })
    c.crawl(stackoverflowspider)
    c.start()

再一次，在脚本中包含以下内容修复了问题

import sys
#The following line (which leads to the folder containing "scrapy.cfg") fixed the problem
sys.path.append(r'C:\Users\WCS\Desktop\stackoverflow')