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javascript - 键入时防止重新呈现主菜单

转载 作者:行者123 更新时间:2023-12-01 15:17:00 25 4
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我的搜索栏组件有问题。执行搜索时,请求成功并且我们得到了所需的显示,但是如果我们想对其进行新的搜索,我们会在输入过程中自动返回到主菜单。你能告诉我如何保持以前搜索的显示而不返回吗?先感谢您

import React, {Component} from 'react'
import ReactDOM from 'react-dom'
import axios from 'axios'

class App extends Component {
constructor(props) {
super(props)
this.state = {
pokemon: '',
resultDatas : '',
search: false,
whiteList: [],
error:''
}
this.handleChange = this.handleChange.bind(this)
this.handleClick = this.handleClick.bind(this)
this.handleSubmit = this.handleSubmit.bind(this)
this.fillWhiteList()
}

//white list function to forbid all special characters
fillWhiteList() {
axios.get('https://pokeapi.co/api/v2/pokemon/')
.then(list => {
const resultList = list.data.results
const theList = resultList.map(theList => theList.name.toLowerCase())
this.setState({
whiteList: theList
})
})
}

//handle the value of the text field and keep letter in lower case
//deletion of white space in typing to not generate errors
//async to have the last letter of the value
handleChange = async function(e) {
await this.setState({
pokemon: e.target.value.toLowerCase().trim(),
resultDatas:''
})
}

//Call API function and data table recovery with 'resultDatas' state
handleSubmit = (e) => {
e.preventDefault()
axios.get('https://pokeapi.co/api/v2/pokemon/' + this.state.pokemon
)
.then( res => {
console.log(res);
const response = res.data
this.onResetField()
this.setState({
resultDatas: response,
search:true,
error: res.status
})
console.log(this.state.error);
})
}

//Home button function
handleClick() {
this.setState({
resultDatas : '',
search: false,
pokemon: ''
})
}

//clear input function when onClick in the cross icon
onResetField() {
const iconReset = document.querySelector('input')
iconReset.value = ''
}

render(){
// Home page display when no value is submitted
if (this.state.search === false || this.state.resultDatas === '') {
return (
<div>
<SearchBar
value={this.handleChange}
submit={this.handleSubmit}
placeholder="Search Pokemon"
/>
<Global
loading="Loading..."
/>
</div>
)
//Error display
}else if (!this.state.whiteList.includes(this.state.pokemon) || this.state.error !== 200) {
return(
<div>
<SearchBar
submit={this.handleSubmit}
value={this.handleChange}
placeholder="Search Pokemon"
/>
<Error
wrong="Pokemon not found please retry"
/>
<PreviousButton
previously={this.handleClick}
return="Back to menu"
/>
</div>
)
// pokemon display
}else {
return(
<div>
<SearchBar
submit={this.handleSubmit}
value={this.handleChange}
placeholder="Search Pokemon"
/>
<PreviousButton
previously={this.handleClick}
return="Back to menu"
/>
<ItemList
list={this.state.resultDatas}
/>
</div>
)
}
}
}

//homepage display
class Global extends Component {
constructor() {
super()
this.state = {
item:[],
isLoaded:false
}
}

//Api call for display home page
APICall() {
axios.get('https://pokeapi.co/api/v2/pokemon/venusaur')
.then(response => {

this.setState({
item: response,
isLoaded:true
})
})
}

render() {
// loading display if request not found
if (!this.state.isLoaded) {
return (
<div>
<div>{this.props.loading}</div>
</div>
)
}else {
return(
<div>
{this.state.item.name}
</div>
)
}
}
}

//Searchbar component
class SearchBar extends Component{
render(){
return(
<form onSubmit={this.props.submit} autoSave="off">
<input
inputMode="tel"
required="required"
autoComplete="off"
type="text"
onChange={this.props.value}
id="searchbar"
placeholder={this.props.placeholder}
/>
</form>
)
}
}

//list of Pokemon component

class ItemList extends Component{
render(){
return(
<div>
{this.props.list.name}
<img src={this.props.list.sprites.front_default} alt="pokemon"/>
</div>
)
}
}

// Previous button component
class PreviousButton extends Component{

render(){
return(
<button onClick={this.props.previously}>{this.props.return}</button>
)
}
}

//error page component
class Error extends Component{
render(){
return(
<div>
{this.props.wrong}
</div>
)
}
}

ReactDOM.render(<App/>, document.querySelector('#root'))
这里有一个代码框,以防它不起作用 https://codesandbox.io/s/keen-ritchie-t5kn8?file=/src/index.js

最佳答案

看起来这就是导致问题的原因。

//handle the value of the text field and keep letter in lower case
//deletion of white space in typing to not generate errors
//async to have the last letter of the value
handleChange = async function(e) {
await this.setState({
pokemon: e.target.value.toLowerCase().trim(),
resultDatas:''
})
}
当您处理输入值更改时,您正在设置 resultDatas到一个空字符串。在您的渲染函数中,您的“主页”正在检查搜索是否等于 false 或者您的 resultDatas 是否为空字符串,因此一旦您开始输入新搜索,它就会重置 resultData 并将您带到主页.
 if (this.state.search === false || this.state.resultDatas === '') {
return (
<div>
<SearchBar
value={this.handleChange}
submit={this.handleSubmit}
placeholder="Search Pokemon"
/>
<Global
loading="Loading..."
/>
</div>
)
}
要解决此问题,您可以这样做,以便键入不会像这样自动清除您的 resultDatas
handleChange = function(e) {
this.setState({
pokemon: e.target.value.toLowerCase().trim()
})
}
**我从这个函数中删除了 async/await 关键字,因为 this.setState 是一个回调,而不是一个 promise 。
带有更改的 CodeSandbox: https://codesandbox.io/s/crazy-rgb-lwzne?file=/src/index.js
附加信息
如果您不想立即被定向到错误页面,那么您将需要跟踪您搜索的当前 pokemon 与正在输入的当前值分开。我已经更新了上面的 CodeSandbox 以包含这些附加信息变化。
如果您查看 CodeSandbox,您会看到现在有一​​个 currentPokemon您所在州的值(value)。在您设置状态的 on submit 函数内部,我正在更新 currentPokemon等于 this.state.pokemon .将它们组合在一起的最后一部分是在渲染函数中。您需要更改错误页面条件以检查您的白名单是否包含 this.state.currentPokemon而不是 this.state.pokemon .

关于javascript - 键入时防止重新呈现主菜单,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/62904476/

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