java - 等待回调而不暂停调用线程。我这样做对吗？

Question

    public class Threadz implements Callable<String>{
    private boolean flag = false;

    @Override
    public String call() throws Exception {
        // TODO Auto-generated method stub
        for(int i = 0; i < 3; i++){
            Thread.sleep(2000);
        }
        flag = true;
        return "Done";
    }

    public boolean isDone(){
        return flag;
    }
}

    public class MyMain {
    public static void main(String[] args) {
        ExecutorService exe = Executors.newSingleThreadExecutor();
        Threadz threadz = new Threadz();
        Callable<String> cthread = threadz;
        Future<String> fut = exe.submit(cthread);

        while(true){
            try {
                if(!threadz.isDone())
                    System.out.println("Do something while waiting...");
                else{
                    System.out.println(fut.get());
                    System.out.print("Do something with the result...");
                    break;
                }
                Thread.sleep(1000);
            } catch (Exception e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
        }
    }
}

我使用上述代码的目标是生成一个将返回结果的线程，但在等待结果时不应暂停调用线程。这确实有效，但我这样做正确吗？有没有正确的方法来做到这一点？另外，可调用线程在返回结果后是否会自动死亡(释放资源和内存)？

谢谢。

Answer 1

String callbackReturn = threadz.get();

如有必要，它会等待计算完成，然后检索其结果。

        ExecutorService exe = Executors.newSingleThreadExecutor();
        Threadz threadz = new Threadz();
        Callable<String> cthread = threadz;
        Future<String> fut = exe.submit(cthread);
        String callbackReturn = threadz.get();

当前线程将在这里等待。如果您不想暂停它，则在其他线程中处理它。