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java - 使用二分查找算法作为基础来实现二分插入

转载 作者:行者123 更新时间:2023-12-01 15:11:23 25 4
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我正在尝试实现二进制插入方法。

目前这个方法非常简单,它需要一个参数,在 while 循环中它搜索一个比参数大的元素(在本例中是一个字符串,是一个人的姓氏),一旦它就中断找到它并将数组的其余部分向右移动。然后将参数插入到中断的位置。

我尝试将其更改为通过借用二分搜索算法来搜索插入位置的算法。但是,我就是无法让它工作。

你能让我知道我做错了什么吗?这是我的代码:

public void insert(Person person) {

String lastName = person.getLastName();

int position = -1; // the position from which the array will be shifted to the right and where the argument will be inserted, will be assigned properly below

int lowerBound = 0;
int upperBound = numElems - 1;
int currIt;

if (numElems == 0)
array[0] = person; // if array empty insert at first position
else
{
while (true)
{
currIt = (lowerBound + upperBound) / 2; //the item to compare with

int result2 = 0;

int result1 = array[currIt].getLastName().compareTo(lastName);

if (array[currIt+1] != null) // if the next element is not null, compare the argument to it
result2 = array[currIt+1].getLastName().compareTo(lastName);

if (currIt == 0 && result1 > 0) // this is when the argument is smaller then the first array element
{
position = 0;
break;
}
// if the position to insert is the last one, or we have found a suitable position between a smaller and a bigger element
else if ( (result1 < 0 && (currIt == numElems-1)) || (result1 < 0 && result2 > 0) ) {
position = currIt+1;
break;
}
else
{
if (result1 < 0) // the place to put it should be in the upper half
lowerBound = currIt + 1;
else
upperBound = currIt - 1; //in the lower half
}

}
}
// position has been set to anything else other -1, then we have found our spot, probably a redundant check but useful for debugging
if (position != -1)
{
//shift array to the right and insert element
for (int j = numElems; j > position; j--)
array[j] = array[j-1];
System.out.println("Inserted an element");
array[position] = person;
numElems++;
}

}

最佳答案

您的“可能[]冗余检查”禁止初始插入。第一次位置为-1。

将顶部的 position 设置为 0 应该可以解决问题。

关于java - 使用二分查找算法作为基础来实现二分插入,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12300948/

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