json - jq - 将复杂的 JSON 解析为字符串

Question

我正在尝试使用 jq 来解析类似于以下内容的 JSON:

{
    "username": "billy",
    "hero": {
        "something": "goeshere"
    },
    "bumper": {
        "bumper2": {
            "bumper3": "splodge"
        }
    },
    "morgan": [{
        "abc": 123
    }, 2, 4, {
        "def": 567
    }],
    "password": "issilly"
}

进入

request.username == 'billy' && request.hero.something == 'goeshere' && request.bumper.bumper2.bumper3 == 'splodge' && request.morgan[0].abc == 123 && request.morgan[1] == 2 && request.morgan[2] == 4 && request.morgan[3].def == 567 && request.password == 'issilly'

到此为止

jq '. | to_entries[] | "request.\(.key) == '\(.value)'"'

这让我走到了那里，但我无法弄清楚如何“深入”到深层嵌套的元素，也无法弄清楚如何将生成的字符串连接到用 '&& ' 分隔的单行中

Answer 1

paths(scalars) 输出表示 . 中字符串和数字路径的数组，使用 getpath 可以获取这些路径的值。所以你所需要的只是一个将路径表示转换为路径表达式的函数，比如:

def pr2pe:
  reduce .[] as $n ([];
    if $n|type == "string"
    then . + [$n]
    elif $n|type == "number" and length
    then .[-1] += "[\($n)]"
    else error("invalid path representation")
    end) | join(".");
[ paths(scalars) as $p
  | "\($p | pr2pe) == \(getpath($p) | tojson)" ]
| join(" && ")

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