java - BlueJ 中的常见错误，但尚未得到解决。与 括号相关

Question

好吧，问题是括号很烦人。由于某种原因它似乎永远不起作用。我检查过其他网站，但这个问题没有得到解决。

import java.util.Scanner;
class x14
    {
        int a;
        int b;
        int c;
        double b2 = Math.pow(b,2);
        double sq = Math.sqrt(b2 - 4*a*c);
        public void main()
        {
            Scanner input = new Scanner(System.in);
            System.out.println("Please input 'a'");
            a = input.nextInt();
            System.out.println("Please input 'b'");
            b = input.nextInt();
            System.out.println("Please input 'c'");
            c = input.nextInt();
            System.out.println("Thank you!");

            double x1 = 0.0;
            double x2 = 0.0;
            x1=(-b+sq)/2a;// Says "Please place ';' here"
            x2=(-b-sq)/2a;// Says "Please place ';' here"
            /* When I Try this : ((-b+sq)/2a);
             * It says i have to place ')' at the end.
             */


            System.out.println("Equation x1 : " + x1);
            System.out.println("Equation x2 : " + x2);
            if(sq > 0)
            System.out.println("The Roots are Real and unequal");
            else if(sq == 0)
            System.out.println("The Roots are Real and Equal");
            else if(sq < 0)
            System.out.println("The Roots are imaginary");
        }
    }

Answer 1

您缺少乘法运算符。

x1=(-b+sq)/2a;// Says "Please place ';' here"
x2=(-b-sq)/2a;// 

应该是:(观察*)

  x1=((-b+sq)/(2*a);// Says "Please place ';' here"
  x2=((-b-sq)/(2*a);//