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java - 使用 POST 将数据从 Java(Android) 发送到 PHP

转载 作者:行者123 更新时间:2023-12-01 14:53:47 25 4
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我在 Android 中有一个应用程序,需要拍照并需要使用 php 将其上传到服务器。

一开始没有问题,可以上传,但是现在需要传递图片上传到服务器的路径。当我尝试发送两个值时,问题就出现了。

我正在使用以下代码:

private  void httpPostFileUpload(String fpath, String uPath){
HttpURLConnection connection = null;
DataOutputStream outputStream = null;
DataInputStream inputStream = null;

//Path where to upload
String uploadPath = uPath;

String pathToOurFile = fpath;
Log.v("file path",fpath.toString());
String urlServer = "http://leojg.alwaysdata.net/tests/androidConnect/handle_upload.php";

String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
String fname = "";

int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;

try
{
File f = new File(pathToOurFile);
fname = f.getName();

FileInputStream fileInputStream = new FileInputStream(f);

URL url = new URL(urlServer);
connection = (HttpURLConnection) url.openConnection();

// Allow Inputs & Outputs
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setUseCaches(false);

// Enable POST method
connection.setRequestMethod("POST");

connection.setRequestProperty("Connection", "Keep-Alive");
connection.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);

outputStream = new DataOutputStream( connection.getOutputStream() );
outputStream.writeBytes(twoHyphens + boundary + lineEnd);

Log.d("path file", pathToOurFile);
Log.d("path up", uploadPath);

outputStream.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + pathToOurFile + "\"" + lineEnd);
outputStream.writeBytes(lineEnd);

bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];

// Read file
bytesRead = fileInputStream.read(buffer, 0, bufferSize);

while (bytesRead > 0)
{
outputStream.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}

outputStream.writeBytes(lineEnd);
outputStream.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

// Responses from the server (code and message)
int serverResponseCode = connection.getResponseCode();
String serverResponseMessage = connection.getResponseMessage();

Log.d("amanda", "upload async finished, server response : " + serverResponseMessage);

fileInputStream.close();
fileInputStream = null;
outputStream.flush();
outputStream.close();
outputStream = null;
f= null;



parent.invokeJs("pictureUploadEnded('" + fname + "')");
this.delete(fpath);

}
catch (Exception ex)
{
Log.d("amanda", "exception uploading image : " + ex.getMessage());
}
}

我很确定问题出在这一行

outputStream.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + pathToOurFile + "\"" + lineEnd);

这是构成帖子正文的那个。我不知道在哪里附加 uploadPath

最佳答案

很好地完成我的类作业:

import java.io.DataOutputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;
import org.json.JSONException;
import org.json.JSONObject;
import org.json.JSONTokener;
import android.os.Environment;
import android.util.Log;

public class HttpPictureUpload implements Runnable {
private String TAG = "HTTPFILEUPLOAD";
private URL connectURL;
private FileInputStream fileInputStream = null;
private String pictureFileName;
private String myName;

public HttpPictureUpload(String urlString, String pictureFileNameString,
String myNameString) {
try {
connectURL = new URL(urlString);

pictureFileName = pictureFileNameString;
myName = myNameString;

} catch (Exception ex) {
Log.i(TAG, "URL Malformatted");
}
}

public void SendPictureNow() {

Sending();
}

private void Sending() {
int maxBufferSize = 1 * 1024*1024*1024;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";

try {

fileInputStream = new FileInputStream(Environment
.getExternalStorageDirectory().toString()
+ "/Picture/"
+ pictureFileName);

Log.e(TAG, "Starting Http File Sending to URL");

// Open a HTTP connection to the URL
HttpURLConnection conn = (HttpURLConnection) connectURL
.openConnection();
conn.setChunkedStreamingMode(maxBufferSize);
// conn.setchu

// Allow Inputs
conn.setDoInput(true);

// Allow Outputs
conn.setDoOutput(true);

// Don't use a cached copy.
conn.setUseCaches(false);

// Use a post method.
conn.setRequestMethod("POST");

conn.setRequestProperty("Connection", "Keep-Alive");

conn.setRequestProperty("Content-Type",
"multipart/form-data;boundary=" + boundary);

DataOutputStream dos = new DataOutputStream(conn.getOutputStream());

// sending appid
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"my_name\""
+ lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(myName);
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + lineEnd);


dos.writeBytes("Content-Disposition: form-data; name=\"file\";filename=\""
+ System.currentTimeMillis() + "\"" + lineEnd);
dos.writeBytes(lineEnd);

int bytesAvailable = fileInputStream.available();

byte[] buffer = new byte[bytesAvailable];

int bytesRead = fileInputStream.read(buffer, 0, bytesAvailable);

while (bytesRead > 0) {
dos.write(buffer, 0, bytesAvailable);
bytesAvailable = fileInputStream.available();
bytesAvailable = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bytesAvailable);
}
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

fileInputStream.close();

dos.flush();

Log.e(TAG,
"File Sent, Response: "
+ String.valueOf(conn.getResponseCode()));

InputStream is = conn.getInputStream();

// retrieve the response from server
int ch;

StringBuffer b = new StringBuffer();

while ((ch = is.read()) != -1) {
b.append((char) ch);

}

String s = b.toString();

Log.i("Response", s);
dos.close();
} catch (MalformedURLException ex) {
Log.e(TAG, "URL error: " + ex.getMessage(), ex);
}

catch (IOException ioe) {
Log.e(TAG, "IO error: " + ioe.getMessage(), ioe);
}
}

@Override
public void run() {
// TODO Auto-generated method stub
}
}

上述类可用于发送图片文件或任何其他文件和一个任何字符串。
使用上面的方法:

HttpPictureUpload uploadPicture=new HttpPictureUpload("http://serverurl.com/webservice.php", "tux.png", "my name is john");
uploadPicture.SendPictureNow();

关于java - 使用 POST 将数据从 Java(Android) 发送到 PHP,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14512901/

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