c++ - Boost program_options 部分键匹配

Question

我正在尝试使用 Boost::program_options 读取配置文件。配置文件如下所示:

hier.arch.y.option_name = 0x5
another.hier.archy.setting_name = 0x1E

我希望能够仅通过“option_name”或“setting_name”进行搜索。我不太担心重复，但如果有一种方法可以选择匹配 2 个子字符串(即“another”+“setting_name”)，那也很棒。

有没有办法让 program_options 基于子字符串匹配？

代码示例:

namespace po = boost::program_options;
po::options_description cmd_opts{"Options"};
po::options_description config_file_opts;
cmd_opts.add_options()
  ("help,h", "Help message")
  ("config_help", "List of configurations available in config file");

po::variables_map vm;
po::store(parse_command_line(argc, argv, combined_opts), vm);
auto parsed_opts = po::parse_config_file<char>(vm.["config_file"].as<std::string>);
po::store(parsed_opts, vm);

配置文件:

foo.bar.setting0 = 0x5
foo.notbar.setting1 = 0x6
bar.notfoo.setting2 = 0x5E

我想分配以下选项:

int setting0;
int setting1;
int setting2;

Answer 1

Q. What does enumerate the parsed options mean?

A. Live On Coliru

for (auto& opt : parsed_opts.options) {
    for (auto& val : opt.value) {
        std::cout 
            << std::quoted(opt.string_key) << "\t-> "
            << std::quoted(val) << std::endl;
    }
}

打印

"foo.bar.setting0"  -> "0x5"
"foo.notbar.setting1"   -> "0x6"
"bar.notfoo.setting2"   -> "0x5E"

模糊匹配，听起来像是正则表达式的工作，也许吧？

Live On Coliru

int setting0 = 0, setting1 = 0, setting2 = 0;

struct { int& target; boost::regex re; }
    fuzzy_opt_desc[] = {
        { setting0, boost::regex{R"(bar\.setting0$)"} },
        { setting1, boost::regex{R"(^foo\..*?setting1$)"} },
        { setting2, boost::regex{R"(setting2$)"} },
    };

for (auto& opt : parsed_opts.options) {
for (auto const& desc : fuzzy_opt_desc) {
    if (boost::regex_search(opt.string_key, desc.re)) {
        for (auto& val : opt.value) {
            desc.target = std::stoul(val, nullptr, 16);
            std::cout 
                << std::quoted(opt.string_key) << "\t-> "
                << desc.target << std::endl;
        }
    }
} }

std::cout << "Finally: " << setting0 << ", " << setting1 << ", " << setting2 << "\n";

打印

"foo.bar.setting0"  -> 5
"foo.notbar.setting1"   -> 6
"bar.notfoo.setting2"   -> 94
Finally: 5, 6, 94