java - 如何在 Java 中发出 http 部分 GET 请求

Question

我正在尝试发出部分 GET 请求，并期望得到 206 响应，但我仍然得到 200 OK。我怎样才能让它响应 206？

这是我编写的代码:

HttpURLConnection urlConn = (HttpURLConnection) url.openConnection();

int start = Integer.parseInt(args[1]);
int end = Integer.parseInt(args[2]);

urlConn.setRequestMethod("GET");
urlConn.setRequestProperty("Range", "bytes=" + start + "-" + end);

if (urlConn.getResponseCode() != HttpURLConnection.HTTP_PARTIAL)
    System.out.println ("File cannot be downloaded.");          
else    
{                                   
    String filepath = url.getPath();
    String filename = filepath.substring (filepath.lastIndexOf('/') + 1);

    BufferedInputStream in = new BufferedInputStream (urlConn.getInputStream());
    BufferedOutputStream out = new BufferedOutputStream (new FileOutputStream (filename));

    int temp;    
    while ((temp = in.read()) != -1)
    {
        out.write ((char)temp);
    }

    out.flush();
    out.close();

    System.out.println ("File downloaded successfully.");
}

Answer 1

How can I make it responded with a 206?

您无法强制服务器尊重您的 Range header 。 HTTP 1.1 规范 says :

"A server MAY ignore the Range header."

<小时/>

您评论:

I know the server does not ignore it. At least shouldn't

显然，服务器 >>IS<< 忽略了 header 。或者，您请求的范围包含整个文档。