java - 打印格式Java

Question

 out.append("Line " + (j+1) + ": ");  
 System.out.print("Line " + (j+1) + ":");
 for (int i = 0; i < lotto.length;i++){
     lotto[i] = r.nextInt(45)+1;                                                                
     out.append(lotto[i] + " ");
     System.out.print(lotto[i] + " ");
 }

现在打印如下

Line 1: 41 7 38 20 38 39 Line 2: 12 35 5 27 4 33 Line 3: 9 3 10 15 35 2

Answer 1

因为您在打印 Line n 后打印新行

您应该在打印数字的内部 for 之后使用 println。

喜欢

// print "Line n"
System.out.print("Line " + (j+1) + ":");

for (int i = 0; i < lotto.length;i++){
    lotto[i] = r.nextInt(45)+1;                                                             
    out.append(lotto[i] + " ");
    // Print in the same line the numbers
    System.out.print(lotto[i] + " ");
}
// Print the new line
System.out.println();