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java - 录音机未处理的异常类型 IOException

转载 作者:行者123 更新时间:2023-12-01 14:38:34 26 4
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目前,我正在尝试在 Android 应用程序中开发一个录音机,最终将其发送到在线服务器,然后进行多播。然而,在我继续之前,我遇到了像未处理的异常类型 IOException 这样的错误。我在出现错误的部分添加了**符号。请帮忙。

package com.example.testproject;

import java.io.File;

import android.app.Activity;
import android.media.MediaPlayer;
import android.media.MediaRecorder;
import android.os.Bundle;
import android.os.Environment;
import android.view.View;

public class Sound extends Activity {

private MediaPlayer mediaPlayer;
private MediaRecorder recorder;
private String OUTPUT_FILE;


@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.audio);

OUTPUT_FILE=Environment.getExternalStorageDirectory()+"/audiorecorder.3gpp";

}

public void buttonTapped(View view){

switch(view.getId()){
case R.id.btnstart:

try {
beginRecording();
}catch(Exception e){
e.printStackTrace();
}

break;

case R.id.btnfinish:

try {
stopRecording();
}catch(Exception e){
e.printStackTrace();
}

break;

case R.id.btnplay:

try {
playRecording();
}catch(Exception e){
e.printStackTrace();
}

break;

case R.id.btnstop:

try {
stopPlayback();
}catch(Exception e){
e.printStackTrace();
}

break;
}

}

private void stopPlayback(){

}

private void playRecording() throws Exception{
ditchMediaPlayer();
mediaPlayer = new MediaPlayer();
mediaPlayer.setDataSource(OUTPUT_FILE);
mediaPlayer.prepare();
mediaPlayer.start();

}

private void ditchMediaPlayer(){
if(mediaPlayer != null)
{
try{
mediaPlayer.release();
}catch(Exception e)
{
e.printStackTrace();
}
}
}

private void stopRecording(){

if(recorder != null)
recorder.stop();

}

private void beginRecording(){

ditchMediaRecorder();
File outputFile = new File(OUTPUT_FILE);

if(outputFile.exists())
outputFile.delete();

recorder = new MediaRecorder();
recorder.setAudioSource(MediaRecorder.AudioSource.MIC);
recorder.setOutputFormat(MediaRecorder.OutputFormat.THREE_GPP);
recorder.setAudioEncoder(MediaRecorder.AudioEncoder.AMR_NB);
recorder.setOutputFile(OUTPUT_FILE);
**recorder.prepare();**
recorder.start();

}

private void ditchMediaRecorder() {
if(recorder != null)
recorder.release();
}

}

最佳答案

您必须处理调用 recorder.prepare() 时可能发生的 IO 错误。请引用the official Java docs有关异常处理的更多信息。

目前,这应该有所帮助:

try {
recorder.prepare();
recorder.start();
} catch (IOException e) {
e.printStackTrace();
}

但请务必在发布应用程序之前实现正确的错误处理。

关于java - 录音机未处理的异常类型 IOException,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16229598/

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