java - 如何将 'cast' 转换为通用对象并使用通用参数执行方法

Question

我有一个类，它在请求时初始化一些 GUI 组件:

public class ComponentInitializer<T extends View>

public abstract void initialize(T object);

现在这是初始化所有组件的代码 fragment :

private <T extends View> void initComponents(View view) {
    // ArrayList<Component<? extends View>> this.componentInitializers
    for (ComponentInitializer<? extends View> initializer : this.componentInitializers) {
        View object = view.findViewById(initializer.getResourceId());

        if (object instanceof CheckBox) {
            ((ComponentInitializer<CheckBox>) initializer).initialize((CheckBox) object);
        }
        else if (object instanceof RadioButton) {
            ((ComponentInitializer<RadioButton>) initializer).initialize((RadioButton) object);
        }
        else if (object instanceof EditText) {
            ((ComponentInitializer<EditText>) initializer).initialize((EditText) object);
        }
    }
}

这有效；我测试过。

但是......有许多对象扩展android.view.View，我懒得为每个扩展View的对象创建一个代码块。

else if (object instanceof ObjectExtendingView) {
    ((ComponentInitializer<ObjectExtendingView>) initializer).initialize((ObjectExtendingView) object);
}

是否可以以某种方式将代码 fragment 减少为一元语句，就像这样:

for (ComponentInitializer<? extends View> initializer : this.componentInitializers) {
    initializer.initialize(object); // Maybe with some casts
}

如果是，怎么办？如果没有，解决方法是什么？

Answer 1

像这样怎么样:

private void initComponents(View view) {
    for (ComponentInitializer<? extends View> initializer : this.componentInitializers) {
        helper(initializer, view);
    }
}

private static <T extends View> void helper(ComponentInitializer<T> initializer, View view) {
        T object = (T)view.findViewById(initializer.getResourceId());
        initializer.initialize(object);
}