c++ - C++ 中的 Play again 选项不适用于数字猜谜游戏

Question

当用户输入“Y”重试时，游戏运行但只给用户 1 次尝试而不是 3 次尝试。程序第一次运行时运行良好，尝试了 3 次。我猜我的循环有问题，它不会重置尝试次数？让我知道是否有任何其他方法可以编写我的代码以使其更清晰/更好。非常感谢。

#include <iostream>
#include <cstdlib>
#include <time.h>
using namespace std;

int guessNum;
int randomNum;
int Tries = 0;

int startGame()
{
    cout << "Number: ";
    cin >> guessNum;
    
    return guessNum, Tries;
}

int main(int a, int b)
{
    while (true) {

     a = guessNum;
     b = Tries;
     char ans;

     // Random number 
     srand(time(NULL));
     randomNum = rand() % 20 + 1;

        // Introduction
        cout << "Guess a number between 1 to 20. You have three attempts." << endl;

        do
        {
            startGame();

            if (guessNum < randomNum)
            {
                cout << "Wrong! It is too low." << endl;
            }

            else if (guessNum > randomNum)
            {
                cout << "Wrong! It is too high." << endl;
            }

            Tries++;
        }

        while (guessNum != randomNum && Tries < 3);

        if (guessNum != randomNum)   // Wrong answer & run out of tries
        {
            cout << "Oops.. All attempts used. The answer is " << randomNum << endl;
        }

        else if (guessNum == randomNum) // User guessed correct number
        {
            cout << "Yes! You are correct!" << endl;
        }

        cout << "Try again?";
        cin >> ans;
        cin.ignore();

        if (ans == 'N')
        {
            cout << "Thanks for playing!";
            break;
        }

    }
}

已编辑 V1

#include <iostream>
#include <ctime>
using namespace std;

int guessNum;

int startGame()
{
    cout << "Number: ";
    cin >> guessNum;
    
    return guessNum;
}

int main()
{
    while (true) {

     int randomNum;
     int Tries = 0;
     char ans;

     // Random number 
     srand(time(NULL));
     randomNum = rand() % 20 + 1;

        // Introduction
       cout << endl << "Guess a number between 1 to 20. You have three attempts." << endl;

        do
        {
            startGame();

            if (guessNum < randomNum)
            {
                cout << "Wrong! It is too low." << endl;
            }

            else if (guessNum > randomNum)
            {
                cout << "Wrong! It is too high." << endl;
            }

            Tries++;
        }

        while (guessNum != randomNum && Tries < 3);

        if (guessNum != randomNum)   // Wrong answer & run out of tries
        {
            cout << "Oops.. All attempts used. The answer is " << randomNum << endl;
        }

        else if (guessNum == randomNum) // User guessed correct number
        {
            cout << "Yes! You are correct!" << endl;
        }

        cout << "Try again? Y/N: ";
        cin >> ans;
        cin.ignore();

        ans = toupper(ans);
        if (ans == 'N')
        {
            cout << endl << "Thanks for playing!";
            break;
        }

        else
        {
            Tries = 0;
        }

    }
}

Answer 1

实际上，您的程序有几个缺陷。

首先，如果你想知道为什么游戏在第一个游戏之后表现出意想不到的方式，你没有在玩游戏后将 Tries 设置回 0。

而且，int startgame() 应该只返回一个变量。您正在尝试同时返回 guessnum 和 Tries。第一个游戏按预期运行的唯一原因是你使用了全局变量，这也被认为是一种不好的做法(如果你没有任何正当理由使用它，一些公司可能会解雇你)。

此外，您从 main 调用中获得了两个 int 函数参数，这是无效的。 (主函数签名应该是 int main(void) 或 int main(int argc, char* argv[]))。我很惊讶编译器没有捕捉到这个错误。

而变量(int a, int b)其实并没有用到。当您发现未使用的变量时，为了便于维护，通常最好删除它们。