java - 从方法返回数组中不重复的数字

Question

我正在尝试使用方法删除重复的数字并返回非重复的数字，实际上我现在陷入了方法中。这是我的代码:

import javax.swing.JOptionPane;
public class duplicateRemover{
     public static void main(String[] args) {
    int[] array = new int[5];

    for (int i=0; i<array.length;i++) {
      String s=JOptionPane.showInputDialog(null,"PLEASE ENTER AN INTEGER:","INTEGERS",JOptionPane.QUESTION_MESSAGE);
      array[i] = Integer.parseInt(s);

    }
    removeDuplicates(array);
   for (int i=0; i<array.length;i++) {
    JOptionPane.showMessageDialog(null,array[i],"UNIQE INTEGERS",JOptionPane.PLAIN_MESSAGE);
   }
     }
public static int[] removeDuplicates(int a []) {
   int []removedDup=new int[a.length];

  for (int i = 0; i < a.length; i++) {
    for (int j = i-1; j < a.length; j++){
      if (a[i] == a[i]) {
        removedDup[i] = j;
        break;

  }

 }

Answer 1

我理解正确吗，你想获取所有只出现一次的整数？这可以通过集合 API 轻松完成。

public static int[] removeDuplicates(int[] a) {
    Set<Integer> unique = new TreeSet<Integer>();
    List<Integer> results = new ArrayList<Integer>();
    for (int i = 0; i < a.length; i++) {
        if (!unique.add(a[i]))
            results.add(a[i]);
    }
    int[] ret = new int[results.size()];
    for (int i = 0; i < results.size(); i++)
        ret[i] = results.get(i);
    return ret;
}