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java - JDBCPreparedStatement 抛出 NullPointerException

转载 作者:行者123 更新时间:2023-12-01 14:31:10 25 4
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有人可以告诉我为什么准备好的语句返回 null 吗?下面是查询数据库的代码:

package beans;
import java.sql.*;
public class ConnectToDB {
private Connection connect;

private final String url = "jdbc:mysql://localhost/";
private final String DBuser = "root";
private final String DBpass = "root";
private final String DBname = "reservation";

private final String Driver = "com.mysql.jdbc.Driver";
public ConnectToDB(){
try{
Class.forName(this.Driver);
this.connect = DriverManager.getConnection(this.url+this.DBname, this.DBuser, this.DBpass);
}catch( ClassNotFoundException | SQLException e){ e.printStackTrace(); }
}
public Connection getConnection(){
return this.connect;
}

private String get_user_info(String username,int index){
/*
* user_info[0] = user_id;
* user_info[1] = username;
* user_info[2] = password;
* user_info[3] = firstname;
* user_info[4] = middle_name;
* user_info[5] = lastname;
* user_info[6] = client_rights;
*
*/
String user_info[] = new String[7];
PreparedStatement pstmt = null;
ResultSet rset = null;
String query = null;
try{
query = "Select * from user where username = ?";
pstmt = this.connect.prepareStatement(query);
pstmt.setString(1, username);
rset = pstmt.executeQuery();
while(rset.next()){
int user_id = rset.getInt("user_id");
user_info[0] = String.valueOf(user_id);
user_info[1] = rset.getString("username");
user_info[2] = rset.getString("password");
user_info[3] = rset.getString("firstname");
user_info[4] = rset.getString("middle_name");
user_info[5] = rset.getString("lastname");
user_info[6] = rset.getString("user_rights");
}
}catch(SQLException e){ e.printStackTrace(); }
finally{
try{
pstmt.close();
rset.close();
}catch(SQLException e){ e.printStackTrace(); }
}
return user_info[index];
}

public int getUserId(String username){
String user_id_from_db = get_user_info(username, 0);
int user_id = Integer.parseInt(user_id_from_db);
return user_id;
}

public String getUsername(String username){ return get_user_info(username, 1); }
public String getPassword(String username){ return get_user_info(username, 2); }
public String getFirstname(String username){ return get_user_info(username, 3); }
public String getMiddlename(String username){ return get_user_info(username, 4); }
public String getLastname(String username){ return get_user_info(username, 5); }
public String getUserRights(String username){ return get_user_info(username, 6); }

public boolean userExists(String username){
boolean queryStatus = false;
if(username.equalsIgnoreCase(getUsername(username)))
queryStatus = true;
else
queryStatus = false;
return queryStatus;
}
}

然后这是调用查询的代码:

<jsp:useBean id="user" class="beans.ConnectToDB" scope="session" />
<jsp:useBean id="aes" class="beans.AES" scope="session" />

String getUsername = request.getParameter("username");
String getPassword = request.getParameter("password");

final String passphrase = "#asdf@1234#";
byte[] password_byte = getPassword.getBytes();
byte[] passphrase_byte = passphrase.getBytes();
byte[] encrypt_password = aes.encrypt(password_byte, passphrase_byte);

if((getUsername != null && !getUsername.isEmpty()) || (getPassword != null && !getPassword.isEmpty())){
String username_from_db = user.getUsername(getUsername);
String password_from_db = user.getPassword(getUsername);

byte[] pass_db_byte = password_from_db.getBytes();
byte[] encrypted_pass_db = aes.encrypt(pass_db_byte, passphrase_byte);

if(getUsername.equalsIgnoreCase(username_from_db) && encrypt_password.equals(encrypted_pass_db)){
response.sendRedirect("home_page.jsp");
}
}
else{ response.sendRedirect("index.jsp"); }

当我调用 getUsername(String username) 方法时,它返回 null,这是抛出的异常:

org.apache.jasper.JasperException: An exception occurred processing JSP page /authenticate_user.jsp at line 29
26: byte[] encrypt_password = aes.encrypt(password_byte, passphrase_byte);
27:
28: if((getUsername != null && !getUsername.isEmpty()) || (getPassword != null && !getPassword.isEmpty())){
29: String username_from_db = user.getUsername(getUsername);
30: String password_from_db = user.getPassword(getUsername);
31:
32: byte[] pass_db_byte = password_from_db.getBytes();


Stacktrace:
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:568)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:470)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)

root cause

java.lang.NullPointerException
beans.ConnectToDB.get_user_info(ConnectToDB.java:61)
beans.ConnectToDB.getUsername(ConnectToDB.java:72)
org.apache.jsp.authenticate_005fuser_jsp._jspService(authenticate_005fuser_jsp.java:110)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:432)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)

最佳答案

你发布的内容太多了。

您需要的是:

beans.ConnectToDB.get_user_info(ConnectToDB.java:61)

在文本编辑器中打开 ConnectToDB.java,到达第 61 行,然后检查该行上的所有对象引用。其中之一为空,因为您没有正确初始化它,或者假设在获得它时它始终为非空。找出是哪一个并正确初始化它。问题解决了。

我认为这不是一个好的解决方案。如果您有 JSP,您就有一个 servlet/JSP 引擎,它应该有一个 JNDI 数据库连接池和命名服务。您应该对其进行设置并外部化您的数据库连接参数。它们不属于您的代码。池将比您更好地管理连接。

您也没有正确关闭资源。它们应该以与创建相反的顺序在 finally block 中关闭,并包装在单独的 try/catch block 中。我会编写一个可以调用的静态实用方法来执行此操作。

package persistence;

public class DatabaseUtils {
private DatabaseUtils() {}

// Similar for ResultSet and Connection
public static void close(Statement st) {
try {
if (st != null) {
st.close();
}
} catch (Exception e) {
// Log the exception
}
}
}

关于java - JDBCPreparedStatement 抛出 NullPointerException,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16857010/

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