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java - 获取异常 OutofMemoryError

转载 作者:行者123 更新时间:2023-12-01 14:19:20 25 4
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我有人在我的应用上加载一堆图像时遇到错误,但我不确定是什么原因造成的。

这是他得到的错误。135号线在底部。
我认为他手机内存不足。他使用的是 2010 年生产的 Desire HD。该方法的作用是从服务器获取图像并将其保存在 HashMap 中。同时将其显示在屏幕上。关于如何防止此 OUTMEMORYERROR 有什么想法吗?

我正在考虑设置一个计数器,如果图像数量超过 20 个,则仅清除 HashMap 。

日志猫:

java.lang.RuntimeException: An error occured while executing doInBackground()
at android.os.AsyncTask$3.done(AsyncTask.java:200)
at java.util.concurrent.FutureTask$Sync.innerSetException(FutureTask.java:274)
at java.util.concurrent.FutureTask.setException(FutureTask.java:125)
at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:308)
at java.util.concurrent.FutureTask.run(FutureTask.java:138)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1088)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:581)
at java.lang.Thread.run(Thread.java:1019)
Caused by: java.lang.OutOfMemoryError: bitmap size exceeds VM budget
at android.graphics.BitmapFactory.nativeDecodeStream(Native Method)
at android.graphics.BitmapFactory.decodeStream(BitmapFactory.java:470)
at android.graphics.BitmapFactory.decodeResourceStream(BitmapFactory.java:336)
at android.graphics.drawable.Drawable.createFromResourceStream(Drawable.java:697)
at android.graphics.drawable.Drawable.createFromStream(Drawable.java:657)
at com.codalata.craigslistchecker.GETTHEIMAGE$ITask.doInBackground(GETTHEIMAGE.java:135)
at com.codalata.craigslistchecker.GETTHEIMAGE$ITask.doInBackground(GETTHEIMAGE.java:1)
at android.os.AsyncTask$2.call(AsyncTask.java:185)
at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:306)

代码:

 public class GETTHEIMAGE {

private HashMap<String, Drawable> ICache;
private static Drawable DefIcon = null;
private BaseAdapter adapt;
private ItemView item;
private int num = 0;

public GETTHEIMAGE(Context c) {
ICache = new HashMap<String, Drawable>();
}

public Drawable GetTheImagedata(
com.codalata.craigslistchecker.Favorites.TheListAdapter theListAdapter,
ImageView ICON_IMG) {
this.adapt = theListAdapter;
String url = (String) ICON_IMG.getTag();
if (ICache.containsKey(url)) {
return ICache.get(url);
} else {
new ITask().execute(url);
return DefIcon;
}
}

public Drawable GetTheImagedata(TheListAdapter adapter, ImageView ICON_IMG) {
this.adapt = adapter;
String url = (String) ICON_IMG.getTag();
if (ICache.containsKey(url)) {
return ICache.get(url);
} else {
new ITask().execute(url);
return DefIcon;
}
}

public Drawable GetTheImagedata2(ItemView itemView, String string) {
this.item = itemView;
String url = string;
if (ICache.containsKey(url)) {
return ICache.get(url);
} else {
new ITask2().execute(url);
return DefIcon;
}
}

private class ITask2 extends AsyncTask<String, Void, Drawable> {
private String Nick;

@Override
protected Drawable doInBackground(String... params) {
Nick = params[0];
InputStream isImage = null;
try {
URL url = new URL(Nick);
isImage = url.openStream();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return Drawable.createFromStream(isImage, "Nick");
}

@Override
protected void onPostExecute(Drawable result) {
super.onPostExecute(result);
if (num == 0) {
item.ivItemimage1.setImageDrawable(result);
}
if (num == 1) {
item.ivItemimage2.setImageDrawable(result);
}
if (num == 2) {
item.ivItemimage3.setImageDrawable(result);
}
if (num == 3) {
item.ivItemimage4.setImageDrawable(result);
}
if (num == 4) {
item.ivItemimage5.setImageDrawable(result);
}
if (num == 5) {
item.ivItemimage6.setImageDrawable(result);
}
if (num == 6) {
item.ivItemimage7.setImageDrawable(result);
}
if (num == 7) {
item.ivItemimage8.setImageDrawable(result);
}
if (num == 8) {
item.ivItemimage9.setImageDrawable(result);
}
if (num == 9) {
item.ivItemimage10.setImageDrawable(result);
}
num++;
}
}

private class ITask extends AsyncTask<String, Void, Drawable> {
private String Nick;

@Override
protected Drawable doInBackground(String... params) {
Nick = params[0];
InputStream isImage = null;
try {
URL url = new URL(Nick);
isImage = url.openStream();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try{
LINE 135 -----> return Drawable.createFromStream(isImage, "Nick");
}catch(Exception e){
e.printStackTrace();
}
return null;
}

@Override
protected void onPostExecute(Drawable result) {
super.onPostExecute(result);
synchronized (this) {
ICache.put(Nick, result);
}
adapt.notifyDataSetChanged();
}
}
}

最佳答案

您需要缩小位图并将缩小的版本加载到内存中。

http://developer.android.com/training/displaying-bitmaps/load-bitmap.html

Use appropriateBitmapFactory.decode method as needed.

这是一个例子:

Out of Memory error with Bitmap

注意:从 Android 3.0(API 级别 11)开始,像素数据与关联的位图一起存储在 Dalvik 堆上。

在 Android 2.3.3(API 级别 10)及更低版本上,建议使用 recycle()。如果您在应用程序中显示大量位图数据,则可能会遇到 OutOfMemoryError 错误。 recycle() 方法允许应用尽快回收内存。

Android 3.0(API 级别 11)引入了BitmapFactory.Options.inBitmap 字段。如果设置此选项,则采用 Options 对象的解码方法将在加载内容时尝试重用现有位图。这意味着位图的内存被重用,从而提高了性能,并消除了内存分配和取消分配。

http://developer.android.com/training/displaying-bitmaps/manage-memory.html

关于java - 获取异常 OutofMemoryError,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17759444/

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