java - 如何使用 charAt() 迭代字符串以验证值是否在范围内？

Question

我正在尝试迭代包含用户输入值的字符串。我想验证用户只输入4个字符，并且所有字符都在1和4之间。例如，提示用户使用逗号输入4个值，因此他们只能输入1,2,3,4。如果他们输入其他内容，则会再次询问。我已经包含了我尝试执行验证的代码部分。我还遇到了无法访问的代码错误，这对我来说没有意义。这是在我关闭 while (true) 循环之后发生的。

        //Entering by ROWS
    //This is for a 4x4 board size using rows
        if (dataSelection == 1) {
        if (boardSize == 1) {
            int row = 1;
            while (row < 5) 
            {
                String row1Values4x4 = "-1";
                while (true) 
                {
                    Scanner firstRow4x4 = new Scanner(System.in);
                    System.out.println("Please enter four values using commas for row " + row); //this needs to loop
                    row1Values4x4 = firstRow4x4.next();
                    row1Values4x4 = row1Values4x4.replaceAll(" ",""); //this is in case user enters numbers with spaces
                    for (int i = 0; i < row1Values4x4.length(); i++) {
                        char c = row1Values4x4.charAt(i);
                        if (row1Values4x4.length() == 7 && c == 48) //I entered 48 in order to test if it is using ascii value (48 = 0) {
                            break;
                        }
                    }
                } //I think I need to include another break in order to escape the second loop? 
                String strArray[] = row1Values4x4.split(","); //This is where I get an unreachable code error 
                int arraySidesInteger[] = new int[strArray.length];
                for (int i = 0;  i < strArray.length;  i++) {
                    arraySidesInteger[i] = Integer.parseInt(strArray[i]);
                }
                fourArray[row-1] = arraySidesInteger;
                for (int i = 0; i < fourArray.length; i++) {
                    for (int j = 0; j < fourArray.length; j++)
                        System.out.print(fourArray[i][j] + " ");
                    System.out.println();
                }
                row++;
                }

如果有请告诉我

Answer 1

您的评论是正确的；你需要在那里进行第二次break。存在的 break 只能跳出 for 循环，但不能跳出 while 循环。

也许而不是

while (true) 
{
    // do some stuff
    for (/* some other stuff */) 
    {
        // even more stuff
        if (/* should we break */) 
        {
            break;
        }
    }
}

你可以尝试类似的事情

boolean done = false;
while (!done) 
{
    // do some stuff
    for (/* some other stuff */) 
    {
        // even more stuff
        if (/* should we break */) 
        {
            done = true;
            break;
        }
    }
}