java - 压缩这段代码？

Question

是否可以以某种方式压缩这两个循环？我必须将它们加倍，因为第二个循环处理被第一个循环忽略的 block

        int count = 1;
        for(int y = 0; y < cuboidClipboard.getHeight(); y++)
        for(int x = 0; x < cuboidClipboard.getWidth(); x++)
        for(int z = 0; z < cuboidClipboard.getLength(); z++)
        {
            BaseBlock baseBlock = cuboidClipboard.getPoint(new Vector(x, y, z));
            Vector relativeVector = new Vector(x,y,z).add(orign);

            Block buildBlock = world.getBlockAt(relativeVector.getBlockX(), relativeVector.getBlockY(), relativeVector.getBlockZ());

            if(Material.getMaterial(baseBlock.getId()).isSolid())
            if(buildBlock.getTypeId() != baseBlock.getId())
                {
                    new PopBlockTask(buildBlock, world, baseBlock).runTaskLater(this, 20+(count*2));
                    count++;
                }
        }

        //we need to place non solid blocks last because they don't attach properly when theres no blocks around them
        for(int y = 0; y < cuboidClipboard.getHeight(); y++)
        for(int x = 0; x < cuboidClipboard.getWidth(); x++)
        for(int z = 0; z < cuboidClipboard.getLength(); z++)
        {
            BaseBlock baseBlock = cuboidClipboard.getPoint(new Vector(x, y, z));
            Vector relativeVector = new Vector(x,y,z).add(orign);

            Block buildBlock = world.getBlockAt(relativeVector.getBlockX(), relativeVector.getBlockY(), relativeVector.getBlockZ());

            if(!Material.getMaterial(baseBlock.getId()).isSolid())  
            if(buildBlock.getTypeId() != baseBlock.getId())
                {
                    new PopBlockTask(buildBlock, world, baseBlock).runTaskLater(this, 20+(count*2));
                    count++;
                }
        }

Answer 1

然后执行第二个循环，您应该只创建非固体 block 的 map /数组列表

if(!Material.getMaterial(baseBlock.getId()).isSolid())  
    // Do the code that's there
else
    // Add to map/list the information you need (x, y, z, count?)
    // If you don't have some way to store the info, you could 
    // just create a small Object to do so or use a Map

然后，不要再次执行整个循环，只需循环 map /列表并创建它们

for(Object o: theList)
{
    // Do the relevant code
}

这不会真正压缩代码，但可以让您不必再次执行大量循环。