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java - 如何使用maven从具有通用模式的多个xsd生成java类

转载 作者:行者123 更新时间:2023-12-01 14:17:35 26 4
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我正在尝试从多个 xsd 文件生成一个 java 类。但是我得到了这个错误。

org.xml.sax.SAXParseException; ... 'somelement' is already defined

我认为这是由于包含多次的常见类型。

如何使用 maven 生成 java 类?

我在目录中有以下模式:

xsd:

  • EXAMPLE_QualifyRS.xsd
  • EXAMPLE_QualifyRQ.xsd
  • EXAMPLE_Peble_CommonTypes.xsd
  • EXAMPLE_CommonTypes.xsd
  • EXAMPLE_SimpleTypes.xsd

EXAMPLE_QualifyRS.xsd

<xs:schema xmlns="http://www.example.org/EXAMPLE/2007/00" xmlns:xs="http://www.w3.org/2001/XMLSchema" targetNamespace="http://www.example.org/EXAMPLE/2007/00" elementFormDefault="qualified" version="1.002" id="EXAMPLE2016.1">
<xs:include schemaLocation="EXAMPLE_CommonTypes.xsd"/>
<xs:include schemaLocation="EXAMPLE_SimpleTypes.xsd"/>
<xs:include schemaLocation="EXAMPLE_Peble_CommonTypes.xsd"/>
<xs:element name="someelement">...</xs:element>

EXAMPLE_Peble_CommonTypes.xsd

<xs:schema xmlns="http://www.example.org/EXAMPLE/2007/00" xmlns:xs="http://www.w3.org/2001/XMLSchema" targetNamespace="http://www.example.org/EXAMPLE/2007/00" elementFormDefault="qualified" version="1.000" id="EXAMPLE2016.1">
<xs:include schemaLocation="EXAMPLE_CommonTypes.xsd"/>

EXAMPLE_QualifyRQ.xsd

<xs:schema xmlns="http://www.example.org/EXAMPLE/2007/00" xmlns:xs="http://www.w3.org/2001/XMLSchema" targetNamespace="http://www.example.org/EXAMPLE/2007/00" elementFormDefault="qualified" version="1.001" id="EXAMPLE2016.1">
<xs:include schemaLocation="EXAMPLE_CommonTypes.xsd"/>
<xs:include schemaLocation="EXAMPLE_SimpleTypes.xsd"/>
<xs:include schemaLocation="EXAMPLE_Peble_CommonTypes.xsd"/>
<xs:element name="someelement">...</xs:element>

下面是我如何在 maven 中生成我的类

<plugin>
<groupId>org.codehaus.mojo</groupId>
<artifactId>jaxb2-maven-plugin</artifactId>
<version>2.4</version>
<executions>
<execution>
<id>example-schema</id>
<phase>generate-sources</phase>
<goals>
<goal>xjc</goal>
</goals>
<configuration>
<xsdPathWithinArtifact>xsd</xsdPathWithinArtifact>
<addGeneratedAnnotation>true</addGeneratedAnnotation>
<laxSchemaValidation>true</laxSchemaValidation>
<laxSchemaValidation>true</laxSchemaValidation>
<readOnly>true</readOnly>
<verbose>true</verbose>
<sources>
<source>src/main/resources/xsd</source>
</sources>
<packageName>com.example</packageName>
</configuration>
</execution>
</executions>
</plugin>

最佳答案

假设您的 common.xsd 中有一个“人”,如下例所示:

<xs:schema xmlns="common.schema.def"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
targetNamespace="common.schema.def"
elementFormDefault="qualified">

<xs:complexType name="Person">
<xs:sequence>
<xs:element name="name" type="xs:string"/>
<xs:element name="age" type="xs:int"/>
</xs:sequence>
</xs:complexType>
</xs:schema>

并且您想在另一个模式中使用它。然后你会这样做:

<xs:schema xmlns="http://www.example.org/EXAMPLE/2007/00"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:common="common.schema.def"
targetNamespace="http://www.example.org/EXAMPLE/2007/00"
elementFormDefault="qualified">
<xs:import namespace="common.schema.def" schemaLocation="common.xsd"/>

<xs:complexType name="someClass">
<xs:sequence>
<xs:element name="person" type="common:Person"/>
<xs:element name="alias" type="xs:string"/>
</xs:sequence>
</xs:complexType>
</xs:schema>

编辑回复评论:

名称冲突的发生是因为您在插件中指定了包名称。然后尝试将具有相同名称的类放在同一个包下。让我们从插件中删除包命名并使用绑定(bind)为每个模式创建所需的包。

你的插件看起来像这样:

<plugin>
<groupId>org.codehaus.mojo</groupId>
<artifactId>jaxb2-maven-plugin</artifactId>
<version>2.4</version>
<executions>
<execution>
<id>example-schema</id>
<phase>generate-sources</phase>
<goals>
<goal>xjc</goal>
</goals>
<configuration>
<xsdPathWithinArtifact>xsd</xsdPathWithinArtifact>
<addGeneratedAnnotation>true</addGeneratedAnnotation>
<laxSchemaValidation>true</laxSchemaValidation>
<laxSchemaValidation>true</laxSchemaValidation>
<readOnly>true</readOnly>
<verbose>true</verbose>
<sources>
<source>src/main/resources/xsd</source>
</sources>
<xjbSources>
<xjbSource>src/main/resources/xjb</xjbSource>
</xjbSources>
</configuration>
</execution>
</executions>
</plugin>

bindings.xjb 看起来像这样:

<jxb:bindings version="1.0"
xmlns:jxb="http://java.sun.com/xml/ns/jaxb"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<jxb:bindings schemaLocation="../xsd/common.xsd">
<jxb:schemaBindings>
<jxb:package name="common.packagename"/>
</jxb:schemaBindings>
</jxb:bindings>
<jxb:bindings schemaLocation="../xsd/someothercommon.xsd">
<jxb:schemaBindings>
<jxb:package name="othercommon.packagename"/>
</jxb:schemaBindings>
</jxb:bindings>
</jxb:bindings>

为了测试它,我使用了另一个带有名为 Person 的元素的 xsd,如下所示:

<xs:schema xmlns="othercommon.schema.def"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
targetNamespace="othercommon.schema.def"
elementFormDefault="qualified">

<xs:complexType name="Person">
<xs:sequence>
<xs:element name="alias" type="xs:string"/>
<xs:element name="id" type="xs:int"/>
</xs:sequence>
</xs:complexType>
</xs:schema>

同时使用两者的架构更新为:

<xs:schema xmlns="http://www.example.org/EXAMPLE/2007/00"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:common="common.schema.def"
xmlns:othercommon="othercommon.schema.def"
targetNamespace="http://www.example.org/EXAMPLE/2007/00"
elementFormDefault="qualified">
<xs:import namespace="common.schema.def" schemaLocation="common.xsd"/>
<xs:import namespace="othercommon.schema.def" schemaLocation="someothercommon.xsd"/>

<xs:complexType name="someClass">
<xs:sequence>
<xs:element name="person" type="common:Person"/>
<xs:element name="otherpersontype" type="othercommon:Person"/>
</xs:sequence>
</xs:complexType>
</xs:schema>

关于java - 如何使用maven从具有通用模式的多个xsd生成java类,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52960720/

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