java - 对树形图中的值进行排序

Question

我读取了一个文本文件并存储在树形图中，每个键都有多个值。例如，

键:A1BG 值:G5730 A4527 E3732 B0166

键:BCA3值:C1478 A4172 D8974 B1432 E2147

键:DB8C 值:N0124 K7414 X9851

因为它是树形图，所以我对所有键进行了排序。现在，我想对与该键对应的所有这些值进行排序。并获取o/p As，

键:A1BG 值:A4527 B0166 E3732 G5730

键:BCA3值:A4172 B1432 C1478 D8974 E2147

键:DB8C 值:K7414 N0124 X9851

我是java新手。任何人都可以帮忙解决这个问题吗？这是我的代码

BufferedReader reader =  new BufferedReader(new FileReader("E:\\book\\datasone.txt"));
Map<String, String> map = new TreeMap<String,String>();
String currentLine;
while ((currentLine = reader.readLine()) != null) 
{
  String[] pair  = currentLine.split("\\s+");
  key = pair[0];
  value = pair[1];
  if(map.containsKey(key))
  {
    value +=  map.get(key);
  }
  else
  {
    map.put(key,value);    
  }
}
for (String name: map.keySet())
{
  String key =name.toString();
  String value = map.get(name).toString();  
  System.out.println(key + " " + value+ " ");  
}   

Answer 1

如果没有重复的值，那么您可以将这些值存储为 TreeSet

public class TestMap {

    public static void main(String[] args) {

        List<String> lines = new ArrayList();
        lines.add("A1BG G5730");
        lines.add("A1BG A4527");
        lines.add("A1BG E3732");
        lines.add("A1BG B0166");
        lines.add("BCA3 C1478");
        lines.add("BCA3 A4172");
        lines.add("BCA3 D8974");
        lines.add("BCA3 B1432");
        lines.add("BCA3 E2147");
        lines.add("DB8C N0124");
        lines.add("DB8C K7414");
        lines.add("DB8C X9851");

        Map<String, Set<String>> map = new TreeMap<String,Set<String>>();
        for(String currentLine : lines){
            String[] pair  = currentLine.split("\\s+");
            String key = pair[0];
            String value = pair[1];
            if(!map.containsKey(key)){
                Set<String> set = new TreeSet<String>();
                map.put(key,set);
            }
            map.get(key).add(value);
        }
        for (String name: map.keySet())
        {
            String key =name.toString();
            System.out.print(key);
            for (String value : map.get(name)){
                System.out.print(" " + value);
            }
            System.out.println();
        }
    }
}

输出

A1BG A4527 B0166 E3732 G5730
BCA3 A4172 B1432 C1478 D8974 E2147
DB8C K7414 N0124 X9851