java - 计算最小值和最大值并四舍五入到近值

Question

我的数学很弱，我需要一些关于最小值和最大值计算的帮助吗？

假设将MinValue 设为 200，MaxValue 设为 1000。

将MinValue和MaxValue除以5(这里只需要显示五个值)

下面是我实现的代码。

double initalValue = 200;
        double finalValue = 1000;
        double range = finalValue - initalValue;
        double designCalRange = range/5;
        double intialrange = initalValue;

        System.out.println("designCalRange::>"+designCalRange);


        System.out.println("AtuaValue::>"+Math.ceil(intialrange));
        System.out.println("RoundOffValue::>"+Math.ceil(intialrange/100)*100 + "\n");

        for (double i = 1; i<=5;i++){
            intialrange += designCalRange;
            System.out.println("\n"+"AtuaValue::>"+Math.ceil(intialrange));
            System.out.println("RoundOffValue::>"+Math.ceil(intialrange/100)*100);
        }
    }

我的输出是**

RoundOffValue::>200.0
RoundOffValue::>400.0
RoundOffValue::>600.0
RoundOffValue::>700.0
RoundOffValue::>900.0
RoundOffValue::>1000.0

**

但应该是:

RoundOffValue::>200.0
RoundOffValue::>400.0
RoundOffValue::>600.0
RoundOffValue::>800.0
RoundOffValue::>1000.0

Answer 1

你是否期待像下面这样

更新为显示 5 个值

   public class Test {
    public static void main(String[] args) {
        int initalValue = 200 ;
        int finalValue = 1000 ;
        int range = finalValue - initalValue;
        int designCalRange = range/4;
        System.out.println("Dividing in to 5 equal intervals");
        System.out.println(initalValue);
        for (double i = 1; i<=3;i++){
            System.out.println((int)(initalValue+designCalRange));
            initalValue = initalValue+ designCalRange;
        }
        System.out.println(finalValue);
    }
}