Java 扫描仪不返回多字变量

Question

我的这部分代码没有按照我的需要工作。我需要从菜单中选择 A、B 或 X，然后输入一个小句子作为描述(多个)和一个成本数字。我可以完美地输入所有数据并返回到菜单(只有输入X后才退出)。但是变量 DamageDesc 的返回字符串仅获取空格之前的第一个单词。我已经尝试了一整夜，但仍然无法让它返回字符串中的所有单词。这是代码，如果有人可以提供帮助。谢谢!

do {
     System.out.println("Damage Repair / Traffic Infringement Data Entry "+ 
        "Menu");
     System.out.println("-------------------------------------------------"+
        "---");

     System.out.println();

     System.out.println("A - Record Damage Repair Details");
     System.out.println("B - Record Traffic Infringement Details");
     System.out.println("X - Exit");

     System.out.println();

     System.out.print("Enter your selection (A/B/X):");
     menuOption = console.next().charAt(0);

     switch (menuOption) {

        case 'A':
        case 'a':
           System.out.print("Enter description of damage repair: ");
           damageDesc = console.next();
           console.nextLine();
           System.out.print("Enter repair cost: ");
           damageCost= console.nextDouble();
           //Place damage description and cost on seperate lines 
           damageDescFinal = String.format(damageDescFinal + "- %s ($%.2f ) \n", damageDesc, damageCost);

           //Also could have used the below
           //damageDescFinal = (damageDescFinal+"- "+damageDesc+
           //   " ($"+damageCost+")"+"\n");

           //All damage costs added together 
           damageCostFinal = damageCostFinal + damageCost;
           System.out.println();
        break;


        case 'B':
        case 'b':
           System.out.print("Enter details of traffic infringement: ");
           fineDesc = console.next();
           console.nextLine();
           System.out.print("Enter traffic fine amount: ");
           fineCost = console.nextDouble();
           //Set fine description and cost on seperate lines
           fineDescFinal = String.format(fineDescFinal + "- %s ($%.2f ) \n", fineDesc, fineCost);

           //Also could have used the below
           //fineDescFinal = fineDescFinal+"- "+fineDesc+
           //   " ($"+fineCost+")"+"\n";
           //All fine costs added together 
           fineCostFinal = fineCostFinal + fineCost;
           System.out.println();
           break;

        case 'X':
        case 'x':
           //Exit the damage and fine menu
           System.out.print("Exiting data entry menu..."+"\n");
           System.out.println();
           break;

        default:
           //Error handling for invalid input
           System.out.print("***ERROR*** Invalid Selection!"+"\n");
           System.out.println();
           break;

     }
  } while (menuOption != 'X' && menuOption != 'x');

Answer 1

也许，您需要使用 nextLine() 来读取整行，而不是 next