Java:正则表达式识别句子中的标点符号并删除它们

Question

我有以下字符串:

String input = "Remove from em?ty sentence 1? Remove from sentence 2! But not from ip address 190.168.10.110!";

我想删除正确位置的标点符号。我的输出需要是:

String str = "Remove from em?ty sentence 1 Remove from sentence 2 But not from ip address 190.168.10.110";

我正在使用以下代码:

while (stream.hasNext()) { 
    token = stream.next();
    char[] tokenArray = token.toCharArray();
    token = token.trim();

    if(token.matches(".*?[0-9]{1,3}\\.[0-9]{1,3}\\.[0-9]{1,3}\\.[0-9]{1,3}[\\.\\?!]+")){
        System.out.println("case2");
        stream.previous();
        int len = token.length()-1;
        for(int i = token.length()-1; i>7; i--){
            if(tokenArray[i]=='.'||tokenArray[i]=='?'||tokenArray[i]=='!'){
                --len;
            }
            else
                break;
        }
        stream.set(token.substring(0, len+1));
    }
    else if(token.matches(".*?\\b[a-zA-Z_0-9]+\\b[\\.\\?!]+")){
        System.out.println("case1");
        stream.previous();
        str = token.replaceAll("[\\.\\?!]+", "");
        stream.set(str);

        System.out.println(stream.next());                          
    }
}

“ token ”是从“输入”字符串发送的。您能否指出我在正则表达式或逻辑方面做错了什么？

标点符号在句子结束时被视为一个标点符号，不存在于 IP 地址中，也不存在于诸如 !true、emp?ty 之类的单词中(保留它们)独自的)。后面也可以跟一个空格或字符串结尾。

Answer 1

您可以使用此模式:

\\p{Punct}(?=\\s|$)

然后什么都不替换。

示例:

String subject = "Remove from em?ty sentence 1? Remove from sentence 2! But not from ip address 190.168.10.110!";
String regex = "\\p{Punct}(?=\\s|$)";
String result = subject.replaceAll(regex, "");
System.out.println(result);