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java - 如何修复从 builder.parse(xmlString) 返回的 SAXException?

转载 作者:行者123 更新时间:2023-12-01 13:57:49 25 4
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我在使用 DocumentBuilderFactory 解析 xml 字符串时遇到问题。当我查看 log.d("File",file) 时,文件包含我想要的 xml 字符串。但是,当我使用 Document doc = db.parse(inputSource) 获取文档时,它返回 SAXException。有人能告诉我我的编码有什么问题吗?谢谢。

        String query="https://maps.googleapis.com/maps/api/directions/xml?origin=33.78917,-118.107626&destination=33.77319,-118.125221&sensor=true";
url = new URL(query);
URLConnection connection = url.openConnection();
HttpURLConnection httpConnection = (HttpURLConnection)connection;
int responseCode = httpConnection.getResponseCode();
InputStreamReader in = new InputStreamReader(httpConnection.getInputStream());
InputStream inputStream = httpConnection.getInputStream();
BufferedReader buf = new BufferedReader(in);

String file="";
while(buf.readLine()!=null){

file+=buf.readLine();
Log.d("File", file);
}

if(responseCode==HttpURLConnection.HTTP_OK){

DocumentBuilderFactory dbf =DocumentBuilderFactory.newInstance();
DocumentBuilder db= dbf.newDocumentBuilder();
//parse xml file
//Document doc = db.parse(file);
InputSource inputSource = new InputSource();
inputSource.setCharacterStream(new StringReader(file));
Log.d("COde",httpConnection.getResponseCode()+"");
try{
Document doc = db.parse(inputSource);
Element el = doc.getDocumentElement();
NodeList nl = el.getElementsByTagName("step");
Log.d("COde",httpConnection.getResponseCode()+"");
Path p;
if(nl!=null && nl.getLength()>0){
for(int i=0; i<nl.getLength();i++){
Node entry =nl.item(i);
NodeList child= entry.getChildNodes();
Log.d("List Size",list.size()+"size");
Element elements = (Element)entry.getChildNodes();
Element sPoint = (Element) elements.getElementsByTagName("start_location");
Element ePoint = (Element)elements.getElementsByTagName("end_location");
Point sP = new Point(sPoint.getFirstChild().getNodeValue(),sPoint.getLastChild().getTextContent());
Point eP = new Point(ePoint.getFirstChild().getTextContent(),ePoint.getLastChild().getTextContent());
String durationValue = elements.getElementsByTagName("duration").item(0).getNodeValue();
Log.d("Duration",durationValue);
String durationText = elements.getElementsByTagName("duration").item(1).getNodeValue();
String instr= elements.getElementsByTagName("html_instructions").item(0).getNodeValue();
String distanceValue =elements.getElementsByTagName("distance").item(0).getNodeValue();
String distanceText = elements.getElementsByTagName("duration").item(1).getNodeValue();
p = new Path(sP,eP,durationText,distanceText,instr);
list.add(p);
Log.d("List Size",list.size()+"size");
}
}
}
finally{}
}
}

catch(MalformedURLException e1){
Log.d("HTTP_CALL","MalformedURLException");
}
catch(ParserConfigurationException e1){
Log.d("HTTP_CALL","ParserConfigurationException");
}
catch(SAXException e1){
Log.d("HTTP_CALL","SAXException");
}catch(IOException e1){
Log.d("HTTP_CALL","IOException");
}

最佳答案

我猜测是因为您正在将其读入 java 字符串,该字符串转义了您作为字符流读回的一些字符。

这似乎对我有用:

InputStream inputStream = connection.getInputStream();
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(inputStream);

关于java - 如何修复从 builder.parse(xmlString) 返回的 SAXException?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19530610/

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