java - 如何使用可变长度字符串标记列

Question

我有一个关于在列中标记字符串的问题我有像这样的表

id  list1   i love dogs2   i like cats and dogs  

and so on

it should be converted to

id  list1   i1   love1   dogs2   i2   like2   cates2   and2   dogs

How do I tokenize this? I tried using this code inside cursor and procedure

SELECT id, regexp_substr(str, '[^ ]+', 1, level) TOKEN
    from test
CONNECT by level <= length(regexp_replace (str, '[^ ]+')) + 1;

但是从 java 调用时速度非常慢。还有其他选择吗？

谢谢安尼尔

Answer 1

正如我在评论中提到的，您可以尝试使用 substr 和 instr 函数而不是 regexp_substr，也许性能会提高您可以接受:

CREATE TABLE test_list_tab (
  id NUMBER,
  str VARCHAR2(100)
);

CREATE TABLE test_tokens_tab (
  id NUMBER,
  token VARCHAR2(100)
);

INSERT INTO test_list_tab VALUES (1, 'i love dogs');
INSERT INTO test_list_tab VALUES (2, 'i like cats and dogs');
INSERT INTO test_list_tab VALUES (3, 'i');
INSERT INTO test_list_tab VALUES (4, 'abc');
INSERT INTO test_list_tab VALUES (5, 'abc i');
INSERT INTO test_list_tab VALUES (6, NULL);

DECLARE
  v_token test_list_tab.str%TYPE;
  v_space_position NUMBER := 1;
  v_prev_space_position NUMBER := 1;
BEGIN
  FOR v_rec IN (SELECT id, str FROM test_list_tab WHERE str IS NOT NULL)
  LOOP
    v_prev_space_position := 0;

    LOOP
      v_space_position := instr(v_rec.str, ' ', v_prev_space_position + 1);
      IF v_space_position > 0 THEN
        v_token := substr(v_rec.str, v_prev_space_position + 1, v_space_position - v_prev_space_position - 1);
      ELSE
        v_token := substr(v_rec.str, v_prev_space_position + 1);
      END IF;

      INSERT INTO test_tokens_tab VALUES (v_rec.id, v_token);

      v_prev_space_position := v_space_position;
      EXIT WHEN v_space_position = 0;
    END LOOP;
  END LOOP;

  COMMIT;
END;

SELECT id, token FROM test_tokens_tab;

输出:

        ID TOKEN ---------- -------         1 i                1 love             1 dogs             2 i                2 like             2 cats             2 and              2 dogs             3 i                4 abc              5 abc              5 i