java - 有没有办法改进这个正则表达式代码？

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我用 Java 编写了这段代码，以便在一些字符(如 >)之前保留空格。 < />如果该行中有多个空格，则会减少到一个。

所以我的代码是。

return source.replaceAll("\\s{2,}", " ").replaceAll("[[\\>][\\s]][[\\s][\\>]]", ">").replaceAll("[[\\<][\\s]][[\\s][\\<]]", "<").replaceAll("[\\s][/>]", "/>");

那么我可以改进我的正则表达式代码吗？

我的测试代码是..

<?xml version="1.0" encoding="UTF-8"?>
<nfeProc xmlns="http://www.portalfiscal.inf.br/nfe"  versao="2.00" > 
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<protNFe xmlns="http://www.portalfiscal.inf.br/nfe" versao="2.00"><infProt><tpAmb>1</tpAmb><verAplic>13_0_94</verAplic><chNFe>31130821483359001109550010002217051649842350</chNFe><dhRecbto>2013-08-07T01:52:47</dhRecbto><nProt>131131174998806</nProt><digVal>JOjHIJzegFkL7ZfGkfAgSwP0+s4=</digVal><cStat>100</cStat><xMotivo>Autorizado o uso da NF-e</xMotivo></infProt></protNFe>
</nfeProc>

Answer 1

如何将 "\\s+" 与替换函数一起使用:string.replaceAll("\\s+", "") 这将删除所有空白，但一个。

X+ 表达式称为量词:指定 X 出现一次或多次

编辑:回复您的评论:

最简单的方法是连续两次调用 replaceAll("\\s+>", ">")，然后调用 replaceAll("\\s+(/>)"，“/>”)<​​；

String a = "asd     > bhsj       <   />   b";
a = a.replaceAll("\\s+>", " >").replaceAll("\\s+(/>)", " />");
System.out.println(a);