java - 从 AJAX 成功函数中检索 ArrayList 元素

Question

我有一个servlet，它将以下内容添加到JSONObject中，rscurbatsmen是结果集，clmmodel_batsman是一个具有playerid、playername、playerscore属性的类。我将如何使用 AJAX 函数从 JSP 中检索元素，就像我对其他变量所做的那样。

 ArrayList curbatsmen = new ArrayList(); 
       while(rscurbatsmen.next()){

       clmmodel_batsman cb = new clmmodel_batsman();
       cb.playerid = new String();
       cb.playerid = rscurbatsmen.getString("playerid");
       cb.playername= new String();
       cb.playername = rscurbatsmen.getString("playerfname");
       cb.playerscore = new String();
       cb.playerscore = rscurbatsmen.getString("runsscored");
       curbatsmen.add(cb);                   

       }

       json.put("curbatsmen", curbatsmen);

以下是我的 AJAX 代码，我检索了我需要的其他变量

<script type="text/javascript">  
    $(document).ready(function(){   
        (function ajaxInterval() {
            $.ajax({  
                url:'clmcontrol_livematchupdate',
                type:'post', 
                dataType: 'json', 

                success: function(data) {  

                    $('#lblscore').html(data.score);//lblscore is a label
                    //Here i need to retrieve elements one by one in order to set the values in particular labels




                },
                complete: function() {
                    // Schedule the next request when the current one has been completed
                    setTimeout(ajaxInterval, 4000);
                }  
            });
        })();


    });  
</script> 

Answer 1

在您的 JSON 中应该有一个节点 curbatsmen ，它将计算为一个对象数组，如下所示:

[
 {"playerId":1,"playerName":"test","playerScore":"score"},
 {"playerId":1,"playerName":"test","playerScore":"score"},
 {"playerId":1,"playerName":"test","playerScore":"score"}
]

因此，您可以使用以下代码:

for(i = 0; i < data.curbatsmen.length; i++){
    batsman = data.curbatsmen[i];
    $("#lblscore").html(batsman.playerScore);

}

或者，无论您实际上想对玩家姓名/分数等做什么。