java - 简化多线阵列

Question

我对 Java 还是个新手，想知道是否有一种方法可以减少我的数组，以便当 5 进入一个数字并且没有剩下的东西时，利用余数运算符开始一个新行？从今天早上开始我一直在试图解决这个问题，但似乎没有取得任何进展。提前谢谢你的帮助。

    public class arrayTest {

        public static void main(String args[]) { 
            final int ARRAY_LENGTH = 25;           // number of ints 
            int array[] = new int[ ARRAY_LENGTH ]; // calculate value for each array element 

            for (int counter = 0; counter < 5; counter++ ) 
                System.out.printf("%d, ", counter); 
            for (int counter = 5; counter < 6; counter++ ) 
                System.out.printf("%d\n", counter);
            for (int counter = 6; counter < 10; counter++ ) 
                System.out.printf("%d, ", counter);
            for (int counter = 10; counter < 11; counter++ ) 
                System.out.printf("%d\n", counter);
            for (int counter = 11; counter < 15; counter++ ) 
                System.out.printf("%d, ", counter);
            for (int counter = 15; counter < 16; counter++ ) 
                System.out.printf("%d\n", counter);
            for (int counter = 16; counter < 20; counter++ ) 
                System.out.printf("%d, ", counter);
            for (int counter = 20; counter < 21; counter++ ) 
                System.out.printf("%d\n", counter);
            for (int counter = 21; counter < 25; counter++ ) 
                System.out.printf("%d, ", counter);
            for (int counter = 25; counter < 26; counter++ ) 
                System.out.printf("%d\n", counter);
        } 

    } 

Answer 1

public class arrayTest
{

public static void main( String args[] )
{
  final int ARRAY_LENGTH = 25; // number of ints 
  int array[] = new int[ ARRAY_LENGTH ];// calculate value for each array element 
  for (int counter = 0; counter < array.length; counter++ ) {
    System.out.printf("%d, ", counter); 
    if (counter%5 == 4) {
    System.out.printf("\n"); // System.out.println() also works
    }
  }
}

}