java - 数组编程 - N 个玩家的 Tic Tac Toe nxn 板

Question

这段代码是一个更大项目的一部分，该项目为 nxn 棋盘上的 n 个玩家制作一个 ti tac toe 游戏，它代表了 tic tac toe 游戏的棋盘。

/** represents a tic tac toe board of a given size */
public class TTTBoard {

/** 2-dimensional array representing the board
 * coordinates are counted from top-left (0,0) to bottom-right (size-1, size-1)
 * board[x][y] == 0   signifies free at position (x,y)
 * board[x][y] == i   for i > 0 signifies that Player i made a move on (x,y)
 */
private int[][] board;

/** size of the (quadratic) board */
private int size;

/** This private static integer i used to make a counter
 */
private static int movecount = 0;

/** constructor for creating a copy of the board
 * not needed in Part 1 - can be viewed as an example 
 */
public TTTBoard(TTTBoard original) {
        this.size = original.size;
        for (int y = 0; y < this.size; y++) {
            for (int x = 0; x < this.size; x++) {
                this.board[x][y] = original.board[x][y];
            }
        }
    }

/** constructor for creating an empty board for a given number of players */
public TTTBoard(int numPlayers) {
        this.size = numPlayers+1;
        this.board = new int[this.getSize()][this.getSize()];
    }

/** checks whether the board is free at the given position */
public boolean isFree(Coordinate c) {
       if (board[c.getX()][c.getY()] == 0) {
           return true;
       } else {
           return false;
           }
    }

/** returns the player that made a move on (x,y) or 0 if the positon is free */
public int getPlayer(Coordinate c) {
        if (isFree(c) == true){
            return board[c.getX()][c.getY()];
        }else{
            return 0;
        }
    }

/** record that a given player made a move at the given position
 * checks that the given positions is on the board
 * checks that the player number is valid 
 */

public void addMove(Coordinate c, int player) {
        if (c.checkBoundaries(size, size) == true && isFree(c) == true && player >= 0 && player <= size-1){
            board[c.getX()][c.getY()] = player;
            movecount++;
        } else {
         throw new IllegalArgumentException("Ivalid move");
        }
    }

/** returns true if, and only if, there are no more free positions on the board */
public boolean checkFull() {
        if (movecount == size*size) {
           return true;
        } else {
           return false;
            }
    }

/** returns 0 if no player has won (yet)
 * otherwise returns the number of the player that has three in a row
 */
public int checkWinning() {
        int b = 1;
        for(int a = 1; a < size-1; a++){
        if (board[a][b] == board[a+1][b] && board[a][b] == board[a-1][b]){
            return board[a][b];
        }else if(board[a][b] == board[a][b+1] && board[a][b] == board[a][b-1]){
            return board[a][b];
        }else if(board[a][b] == board[a+1][b-1] && board[a][b] == board[a-1][b+1]){
            return board[a][b];
        }else if(board[a][b] == board[a+1][b+1] && board[a][b] == board[a-1][b-1]){
            return board[a][b];
        }
        }
        for(int a = 1; a < size-1; a++){
            if (board[b][a] == board[b+1][a] && board[b][a] == board[b-1][a]){
                return board[b][a];
            }else if(board[b][a] == board[b][a+1] && board[b][a] == board[b][a-1]){
                return board[b][a];
            }else if(board[b][a] == board[b+1][a-1] && board[b][a] == board[b-1][a+1]){
                return board[b][a];
            }else if(board[b][a] == board[b+1][a+1] && board[b][a] == board[b-1][a-1]){
                return board[b][a];
            }
            }
        return 0;
    }

/** getter for size of the board */
public int getSize() {
        return this.size;
    }
}

由于我运行洞程序的测试表明 addMove 有问题，为什么我知道这是因为我没有收到错误消息，但程序也没有执行我所执行的操作:

public void addMove(Coordinate c, int player) {
        if (c.checkBoundaries(size, size) == true && isFree(c) == true && player >= 0 && player <= size-1){
            board[c.getX()][c.getY()] = player;
            movecount++;
        } else {
         throw new IllegalArgumentException("dumpass!");
        }
    }

我看起来代码没有正确记录 Action ，而且我看不出我在这里做错了什么。x 和 y 坐标，我的板来自另一个类坐标，这就是为什么我使用 getter 来获取它们。

Answer 1

我认为至少在玩家和广场职业处理上存在问题。当一个方 block 空闲时，您将其设置为 0(并且您的 isFree(Coordinate c) 和 getPlayer(Coordinate c) 方法可以接受)。

但是，在 addMove(Coordinate c, int player)方法，你检查 player >= 0 && player <= size - 1 。然后你设置board[c.getX()][c.getY()]至player 。如果有 2 个玩家，大小等于 2，并且 player必须介于 0 或 1 之间。轮到第一个玩家时，player变量肯定设置为 0，因此棋盘方格也设置为 0，这意味着该方格是空闲的。 “占领者玩家”和自由状态之间存在混淆。

我认为你应该替换 player >= 0 && player <= size - 1与 player > 0 && player <= size 。因此，一个空闲的方格值(value) 0，第一个玩家占据的方格值(value) 1，第二个玩家占据的方格值(value) 2。

此外，正如 @DanielJacobson 在其评论中所述，您应该替换 isFree(c) == true和c.checkBoundaries(size, size) == true与 isFree(c)和c.checkBoundaries(size, size) .