scala 以格式保存到数组

Question

我有两个 val:

// 0~250::250~500::500~750::750~1000
val step_x_ranges = stepsAsString.mkString("::")

// 1::22::7::16
val step_y = histogram_final.map{case (x , y) => y}.mkString("::")

我想将它保存到一个 Array 中，例如:

0~250::1
250~500::22
500~750::7
750::1000::16

但还是没有尝试:请帮助我

这是我的错误代码:

var toArray : Array[String] = Array()
   for (i <- 0 to 3)
   {
     val ArrayRow = step_x_ranges(i) + "::" + step_y(i)
     toArray = toArray :+ ArrayRow
   }
   println(toArray(0)) 
   println(toArray(1))

结果:

0::4
~::8 

Answer 1

使用zip:

scala> val step_x_ranges = Array("0~250", "250~500", "500~750","750~1000")
step_x_ranges: Array[String] = Array(0~250, 250~500, 500~750, 750~1000)

scala> val step_y = Array(1, 22, 7, 16)
step_y: Array[Int] = Array(1, 22, 7, 16)

scala> val result = step_x_ranges.zip(step_y).map{case (x, y) => s"$x::$y"}
res1: Array[String] = Array(0~250::1, 250~500::22, 500~750::7, 750~1000::16)
scala> scala.tools.nsc.io.File("test.txt").writeAll(result.mkString("\n"))

和测试.txt:

0~250::1
250~500::22
500~750::7
750~1000::16